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sattari [20]
3 years ago
15

Aiden had 55 minutes to finish a quiz. He finished early and had a read his book while the rest of the class finished their quiz

. How long did it take Aiden to complete his quiz written in decimal form?​
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0
Ficbeicyeveocyrvwochtbdocurbrosh
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-19.5 degrees celcius in 2.4 minutes What is the average temperature per minute the container cooled?
klemol [59]
Idk tbh man I think sumbody else will answer
4 0
3 years ago
r. Yi buys vegetables at a market. He purchases 6 pounds of potatoes, p, and 3 pounds of onions, n, for $18. Onions cost twice a
ad-work [718]

Answer:

  • The equation 2n = p should be 2p = n.
  • The actual cost of the onions is $3.00 per pound.
  • Potatoes cost $1.50 per pound.

Step-by-step explanation:

The wording "onions cost twice as much as potatoes" is understood to mean the cost per pound of onions (n) is equal to two times the cost per pound of potatoes (2p). Then the appropriate equation would be ...

  2p = n

Then the solution is ...

  6p +3(2p) = 18

  12p = 18

  p = 18/12 = 1.50

  n = 2p = 2(1.50) = 3.00

__

The equation should be 2p = n; onions cost $3.00 per pound; potatoes cost $1.50 per pound.

5 0
3 years ago
Select the correct answer.
VLD [36.1K]

Answer:

I think the answer is B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
9 is the geometric mean between 4 and which other number?
KonstantinChe [14]
Answer is A. 20.25

cause 20.25 x 9 = 81
√81 = 9
so 9 is the geometric mean <span>between 4 and 20.25</span>
5 0
4 years ago
assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
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