Answer is 11/6
Hope this helps :)
Answer:
Swing two arcs above and below the radius.
Step-by-step explanation:
We want to determine which statement is NOT a step used when constructing an inscribed hexagon?
1. Swing two arcs above and below the radius.
False
2. Draw a radius of the circle using a straightedge. True
3. Place the compass on the point where the circle and radius intersect. True
4. Swing an arc the length of the radius from the point on the circle. True
The first choice is the correct answer.
Let's say the integer is n and the other one is j
so n=2j+17
And n×j=-36
If you cancel j out, you're left with 3n=-55
so n=-18 and 1/3
From the question
We are given the points
![K(-6,6),P(-3,-2)](https://tex.z-dn.net/?f=K%28-6%2C6%29%2CP%28-3%2C-2%29)
Finding the slopre, m
Slope is calculated using
![m=\frac{y_{2_{}}-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_%7B2_%7B%7D%7D-y_1%7D%7Bx_2-x_1%7D)
From the given points
![\begin{gathered} x_1=-6,y_1=6 \\ x_2=-3,y_2=-2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x_1%3D-6%2Cy_1%3D6%20%5C%5C%20x_2%3D-3%2Cy_2%3D-2%20%5Cend%7Bgathered%7D)
Therefore,
![\begin{gathered} m=\frac{-2-6}{-3-(-6)} \\ m=\frac{-8}{-3+6} \\ m=\frac{-8}{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20m%3D%5Cfrac%7B-2-6%7D%7B-3-%28-6%29%7D%20%5C%5C%20m%3D%5Cfrac%7B-8%7D%7B-3%2B6%7D%20%5C%5C%20m%3D%5Cfrac%7B-8%7D%7B3%7D%20%5Cend%7Bgathered%7D)
Therefore, m = -8/3
The next thing is to find
![\mleft\Vert m\mright?](https://tex.z-dn.net/?f=%5Cmleft%5CVert%20m%5Cmright%3F)
A slope parallel to m
For parallel lines, slopes are equal
Therefore,
![\mleft\Vert m=-\frac{8}{3}\mright?](https://tex.z-dn.net/?f=%5Cmleft%5CVert%20m%3D-%5Cfrac%7B8%7D%7B3%7D%5Cmright%3F)
Next, we are to find
![\perp m](https://tex.z-dn.net/?f=%5Cperp%20m)
A slope perpendicular to m
For perpendicular lines, the product of the slopes = -1
Therefore
![\perp m=-\frac{1}{m}](https://tex.z-dn.net/?f=%5Cperp%20m%3D-%5Cfrac%7B1%7D%7Bm%7D)
Hence,
![\begin{gathered} \perp m=-\frac{1}{-\frac{8}{3}} \\ \perp m=\frac{3}{8} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cperp%20m%3D-%5Cfrac%7B1%7D%7B-%5Cfrac%7B8%7D%7B3%7D%7D%20%5C%5C%20%5Cperp%20m%3D%5Cfrac%7B3%7D%7B8%7D%20%5Cend%7Bgathered%7D)
Therefore,
![\perp m=\frac{3}{8}](https://tex.z-dn.net/?f=%5Cperp%20m%3D%5Cfrac%7B3%7D%7B8%7D)
Next, we are to find the distance KP
Using the formula
![KP=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=KP%3D%5Csqrt%5B%5D%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
This gives
![\begin{gathered} KP=\sqrt[]{(-3-(-6))^2+(-2-6)^2} \\ KP=\sqrt[]{3^2+(-8)^2} \\ KP=\sqrt[]{9+64} \\ KP=\sqrt[]{73} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20KP%3D%5Csqrt%5B%5D%7B%28-3-%28-6%29%29%5E2%2B%28-2-6%29%5E2%7D%20%5C%5C%20KP%3D%5Csqrt%5B%5D%7B3%5E2%2B%28-8%29%5E2%7D%20%5C%5C%20KP%3D%5Csqrt%5B%5D%7B9%2B64%7D%20%5C%5C%20KP%3D%5Csqrt%5B%5D%7B73%7D%20%5Cend%7Bgathered%7D)
Therefore,
![\text{Distance }=\sqrt[]{73}](https://tex.z-dn.net/?f=%5Ctext%7BDistance%20%7D%3D%5Csqrt%5B%5D%7B73%7D)
Next, equation of the line
The equation can be calculated using
![\frac{y-y_1}{x-x_1}=m](https://tex.z-dn.net/?f=%5Cfrac%7By-y_1%7D%7Bx-x_1%7D%3Dm)
By inserting values we have
![\begin{gathered} \frac{y-6}{x-(-6)}=-\frac{8}{3} \\ \frac{y-6}{x+6}=-\frac{8}{3} \\ y-6=\frac{-8}{3}(x+6) \\ y-6=-\frac{8}{3}x-6(\frac{8}{3}) \\ y-6=-\frac{8}{3}x-16 \\ y=-\frac{8}{3}x-16+6 \\ y=-\frac{8}{3}x-10 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7By-6%7D%7Bx-%28-6%29%7D%3D-%5Cfrac%7B8%7D%7B3%7D%20%5C%5C%20%5Cfrac%7By-6%7D%7Bx%2B6%7D%3D-%5Cfrac%7B8%7D%7B3%7D%20%5C%5C%20y-6%3D%5Cfrac%7B-8%7D%7B3%7D%28x%2B6%29%20%5C%5C%20y-6%3D-%5Cfrac%7B8%7D%7B3%7Dx-6%28%5Cfrac%7B8%7D%7B3%7D%29%20%5C%5C%20y-6%3D-%5Cfrac%7B8%7D%7B3%7Dx-16%20%5C%5C%20y%3D-%5Cfrac%7B8%7D%7B3%7Dx-16%2B6%20%5C%5C%20y%3D-%5Cfrac%7B8%7D%7B3%7Dx-10%20%5Cend%7Bgathered%7D)
Therefore the equation is