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balandron [24]
3 years ago
11

12

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0

Answer:

it 5.5⋅10−^8m

Step-by-step explanation:

Unless I'm missing something important here, you can find the difference between the two wavelengths by subtracting one from the other. Since you're interested in finding how much longer the wavelength associated with the orange light is, subtract the wavelength of the green light from the wavelength of the orange light. You know that the two measured wavelengths are 6.15 ⋅ 10 − 7 m → orange light 5.6 ⋅ 10 − 7 m → green light Therefore, the difference between the two wavelengths will be Δ wavelength = 6.15 ⋅ 10 − 7 m − 5.6 ⋅ 10 − 7 m = 5.5 ⋅ 10 − 8 m

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Need some math help please!
stellarik [79]

Hello!

In our triangle, c is the hypotenuse. We are given an adjacent side length to our angle. This means we will use the cosine. Let's find it first.

cos54≈0.59

This gives us the equation below.

0.59=9/c

0.59c=9

c≈15.25

Therefore, c is equal to about 15.25

I hope this helps!

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4a^3b^5 - 16a^5b^2 + 12a^2b^3 =
4a^2b^2 (ab^3 - 4a^3 + 3b) <==
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The anset to your question is 1/2

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Answers................ ​
Andreyy89

Answer:

x=1

Step-by-step explanation:

log2( x^2 -x+2) = 1+2log2(x)

Rewriting 1 as log2(2)

log2( x^2 -x+2) = log2(2)+2log2(x)

We know that a log b = log a^b

log2( x^2 -x+2) = log2(2)+log2(x^2)

we know log a + log b = log (ab)

log2( x^2 -x+2) = log2(2*x^2)

Since the bases are the same the terms inside must be equal

x^2 -x+2 = 2x^2

Subtract 2x^2 from each side

-x^2 -x+2 = 0

Multiply by -1

x^2 +x-2 = 0

Factor

(x+2)(x-1)=0

Using the zero product property

x+2 = 0  x-1=0

x=-2  x=1

Checking the solutions

log2( x^2 -x+2) = 1+2log2(x)

X cannot be negative because 2 log2(x) cannot be negative

log2( 1^2 -1+2) = 1+2log2(1)

x=1

6 0
3 years ago
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