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astra-53 [7]
2 years ago
10

To the nearest centimeter, what is the area of the shaded sector in the circle shown below? A. 12 cm2 B. 151 cm2 C. 23 cm2 D. 13

8 cm2
Mathematics
1 answer:
vovikov84 [41]2 years ago
6 0

Step-by-step explanation:

what are the sides given?

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Suppose that--in any given time period--a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcomes
Leviafan [203]

Answer:

x =45 and y = 23

Step-by-step explanation:

6 0
3 years ago
the length of a rectangle is 2 times in width if the perimeter of the rectangle is 36 in find its length and width​
Basile [38]

Answer:

Length=12 inches Width=6 inches

Step-by-step explanation:

X can stand for the width. 2x can stand for the length since it is twice the width. The perimeter would then equal 6x. 6x is equal to 36. Divide by 6 to isolate x. X equals 6 inches. So twice the width would be 12 inches.

8 0
3 years ago
7(2c−5d)−3(d−2c) What’s this answer
Kazeer [188]
1. 7(2c-5d)-3(d-2c)
2. 14c-35d-3d+6c (DISTRIBUTE)
3. Answer: 20c-38d (PUT TOGETHER LIKE TERMS AND SOLVE)
4 0
3 years ago
(x + 5)2 + (y - 7)2 = 36, its radius is
sashaice [31]
6 because the 36 is r² where r is the radius, r² = 36; we have to isolate the r so it's by its self, so square root both sides, r = 6 
5 0
3 years ago
Two cargo ships spot a signal fire on a small island. The captains know they are 140 feet
Irina18 [472]

The distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

Explanation:

It is given that two ships A and B are at a distance 140 ft from each other.

The angle formed by ship A is 82º and the angle formed by ship B is 78º.

To determine the distance from ship B to the signal fire at point C, we need to know the another angle.

Hence, we have,

\begin{aligned}\angle A+\angle B+\angle C &=180^{\circ} \\82^{\circ}+78^{\circ}+\angle C &=180^{\circ} \\160^{\circ}+\angle C &=180^{\circ} \\\angle C &=20^{\circ}\end{aligned}

Now, we shall solve the problem using the law of sines,

\frac{\sin A}{a}=\frac{\sin C}{c}

Substituting the values, we have,

\frac{\sin 82^{\circ}}{a}=\frac{\sin 20^{\circ}}{140}

\frac{0.9903}{a}=\frac{0.3420}{140}

Simplifying, we get,

a=\frac{0.9903 \times 140}{0.3420}

a=405.4

Thus, the distance from Ship B to the signal fire at point C is 405.4 \mathrm{ft}

4 0
3 years ago
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