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goldfiish [28.3K]
2 years ago
12

In the figure below, angle y and angle x form vertical angles. Angle y forms a straight line with the 80° angle and the 60° angl

e.
A straight line is shown and is marked with three angles. The first angle measures 80 degrees. The second angle measures 60 degrees. The third angle is labeled y. The line between the 60 degree angle and angle y extends below the straight line. The angle formed is labeled angle x.

Write and solve an equation to determine the measure of angle x.
Mathematics
1 answer:
Yuri [45]2 years ago
4 0

Answer:Then ask a neighbor for help

Step-by-step explanation:Hey just breath

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How to make a decimal a mixed number​
lianna [129]

Answer:Step 1: Write down the decimal divided by 1, like this: decimal1

Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

Step 3: Simplify (or reduce) the fraction

Example: Convert 0.75 to a fraction

Step 1: Write down 0.75 divided by 1:

0.751

Step 2: Multiply both top and bottom by 100 (because there are 2 digits after the decimal point so that is 10×10=100):

× 100

right over arrow

0.751 = 75100

right under arrow

× 100

(Do you see how it turns the top number

into a whole number?)

Step 3: Simplify the fraction (this took me two steps):

÷5 ÷ 5

right over arrow right over arrow

75100 = 1520 = 34

right under arrow right under arrow

÷5 ÷ 5

Answer = 34

Step-by-step explanation:

5 0
3 years ago
An open metal tank of square base has a volume of 123 m^3
snow_lady [41]

Answer:

  a) h = 123/x^2

  b) S = x^2 +492/x

  c) x ≈ 6.27

  d) S'' = 6; area is a minimum (Y)

  e) Amin ≈ 117.78 m²

Step-by-step explanation:

a) The volume is given by ...

  V = Bh

where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:

  123 = x^2·h

  h = 123/x^2

__

b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

S=x^2+Ph=x^2+(4x)\dfrac{123}{x^2}\\\\S=x^2+\dfrac{492}{x}

__

c) The derivative of the area with respect to x is ...

S'=2x-\dfrac{492}{x^2}

When this is zero, area is at an extreme.

0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583

__

d) The second derivative is ...

S''=2+\dfrac{2\cdot 492}{x^3}=2+\dfrac{2\cdot 492}{246}=6

This is positive, so the value of x found represents a minimum of the area function.

__

e) The minimum area is ...

S=x^2+\dfrac{2\cdot 246}{x}=(246^{\frac{1}{3}})^2+2\dfrac{246}{246^{\frac{1}{3}}}=3\cdot 246^{\frac{2}{3}}\approx 117.78

The minimum area of metal used is about 117.78 m².

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Hoochie [10]

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