Answer:Step 1: Write down the decimal divided by 1, like this: decimal1
Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)
Step 3: Simplify (or reduce) the fraction
Example: Convert 0.75 to a fraction
Step 1: Write down 0.75 divided by 1:
0.751
Step 2: Multiply both top and bottom by 100 (because there are 2 digits after the decimal point so that is 10×10=100):
× 100
right over arrow
0.751 = 75100
right under arrow
× 100
(Do you see how it turns the top number
into a whole number?)
Step 3: Simplify the fraction (this took me two steps):
÷5 ÷ 5
right over arrow right over arrow
75100 = 1520 = 34
right under arrow right under arrow
÷5 ÷ 5
Answer = 34
Step-by-step explanation:
Answer:
a) h = 123/x^2
b) S = x^2 +492/x
c) x ≈ 6.27
d) S'' = 6; area is a minimum (Y)
e) Amin ≈ 117.78 m²
Step-by-step explanation:
a) The volume is given by ...
V = Bh
where B is the area of the base, x^2, and h is the height. Filling in the given volume, and solving for the height, we get:
123 = x^2·h
h = 123/x^2
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b) The surface area is the sum of the area of the base (x^2) and the lateral area, which is the product of the height and the perimeter of the base.

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c) The derivative of the area with respect to x is ...

When this is zero, area is at an extreme.
![0=2x -\dfrac{492}{x^2}\\\\0=x^3-246\\\\x=\sqrt[3]{246}\approx 6.26583](https://tex.z-dn.net/?f=0%3D2x%20-%5Cdfrac%7B492%7D%7Bx%5E2%7D%5C%5C%5C%5C0%3Dx%5E3-246%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B246%7D%5Capprox%206.26583)
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d) The second derivative is ...

This is positive, so the value of x found represents a minimum of the area function.
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e) The minimum area is ...

The minimum area of metal used is about 117.78 m².
A line being rotated in such a way I would think would be A
Answer:
You get the answer by seeing if the line on the graph passes through the origin and if it does you see how many there is for every 1 thing.
Step-by-step explanation: