You have to divide 77 by 4 and then the reminder will be 1 so only one check will be there in the final envelop.
The zeros of given function
is – 5 and – 3
<u>Solution:</u>
![\text { Given, equation is } y=x^{2}+8 x+15](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Given%2C%20equation%20is%20%7D%20y%3Dx%5E%7B2%7D%2B8%20x%2B15)
We have to find the zeros of the function by rewriting the function in intercept form.
By using intercept form, we can put value of y as to obtain zeros of function
We know that, intercept form of above equation is ![x^{2}+8 x+15=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%2B8%20x%2B15%3D0)
![\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Splitting%20%7D%208%20x%20%5Ctext%20%7B%20as%20%7D%285%2B3%29%20x%20%5Ctext%20%7B%20and%20%7D%2015%20%5Ctext%20%7B%20as%20%7D%205%20%5Ctimes%203)
![\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Crightarrow%20x%5E%7B2%7D%2B%285%2B3%29%20x%2B5%20%5Ctimes%203%3D0%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%20x%5E%7B2%7D%2B5%20x%2B3%20x%2B5%20%5Ctimes%203%3D0%7D%5Cend%7Barray%7D)
Taking “x” as common from first two terms and “3” as common from last two terms
x (x + 5) + 3(x + 5) = 0
(x + 5)(x + 3) = 0
Equating to 0 we get,
x + 5 = 0 or x + 3 = 0
x = - 5 or – 3
Hence, the zeroes of the given function are – 5 and – 3
Answer:
last graph
Step-by-step explanation:
The answer is 3 because if you were to round 2.9 the next whole up from that is 3
Answer:
Step-by-step explanation:
area=4×22/7×14²=4×22×28=2464 units²