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3 years ago

15

are yall just using this thing to cheat on your tests LOL i swear im seeing so many people asking questions that look like theyr

e exactly from their homework or an assignment

1 answer:

Oliga [24]3 years ago

5 0

Answer:

that's what most people use it for I believe

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What radian measure is equivalent to 75 degrees

koban [17]

WORK

5π/12
75∘⋅π/180∘=5π/12

Therefore the answer not rounded is 1.309 radians

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3 years ago

If two angles are complementary and one angle is xº what is the measure of the other angle?

Rainbow [258]

Answer:

Step-by-step explanation:

Measure of second angle = 90° - x°

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2 years ago

If p is the midpoint of line xy, xp=11-6b and py=6-b, find xp

MariettaO [177]

Since p is the midpoint then xp and pay must equal each other
So, 11-6b=6-b
Solve for b
11-6b=6-b
-6 -6
5-6b=-b
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3 years ago

Find the indefinite integral. (Use C for the constant of integration.)

mart [117]

Answer:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

$u=(x^3-x^2+x)$

Then

$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

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2 years ago

Please answer this problem.

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1. 1,200
2. 800
3. 2,000

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3 years ago