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3 years ago

When describing a rotation, what information would you need to include? *

Mathematics

1 answer:

Solnce55 [7]3 years ago

7 0

Answer:

A shape can be rotated. Every point on the shape is turned by an angle about a center of rotation. To describe a rotation, we need to say what angle the shape has been turned by and where the center of rotation is.

Step-by-step explanation:

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Name the operation you should preform first

Colt1911 [192]

1. 4 times 6
2. 8 divided by 2
3. 4 squared 2

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3 years ago

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For her new MP3 player, Alicia wants a case that is 3 2/5 in. long. The online store shows case sizes in decimal measurements. W

Ivan

Answer:

C.) 3.4 in.

Step-by-step explanation:

Because I did the test and got it right.

5 0

3 years ago

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Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage. Determine the weight of a 170 cm steel bar

Bumek [7]

The weight of a 170 cm steel bar will be 5 Kg

Step-by-step explanation:

Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage.

1 kg = 1000 gm

So the weight of 1 cm steel bar will be $\frac{4 }{136}$ kg

Weight of 1 cm bar = $\frac{4000}{136}$ gm

Let the weight of a 170 cm steel bar will be $\frac{4000 }{136}$ × $170$ gm

⇒ $4000$ × $1.25$ gm

⇒ 5000 gm

⇒5 kg

Hence, the weight of a 170 cm steel bar will be 5 Kg

4 0

3 years ago

For the function y=-3+ cos (x + 4)], what is the minimum value?

Mrac [35]

Answer:

-4 is the mimumum of y=-3+cos(x+4)

Step-by-step explanation:

The minimum value of y=cos(x) is -1.

The minimum value of y=cos(x+4) is still -1; the +4 inside the cosine function only affected the horizontal shift.

The minimum value of y=-3+cos(x+4) is -3-1 which is -4. This brought the graph down 3 units so if the minimum was previously -1 and it got brought down 3 units then it's new minimum is -4.

5 0

3 years ago

For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?

DaniilM [7]

<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

$x\neq 1$

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

$\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]$

Now, the determinant of this matrix is:

$\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1$

Hence,

$-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1$

4 0

3 years ago