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Whitepunk [10]
3 years ago
10

What is the least common multiple of 2, 3, and 20?

Mathematics
2 answers:
beks73 [17]3 years ago
5 0

Answer:

60

Step-by-step explanation:

20x3=60

2x30=60

3x20=60

60 is the least common multiple.

tia_tia [17]3 years ago
3 0

Answer:

60

Step-by-step explanation:

The least common multiple of 2 and 20 is 20.

The only factor that is shared with 20 and 3 is 1. Therefore, the least common multiple will have to be 20*3, which is 60.

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Which trigonometric ratio is correct for triangle DEF? (Hint: Use Pythagorean Theorem first) A.) Sin(D)= 24/7 B.) Tan(D)= 24/25
Tanya [424]

Answer:

Cos E= 24/25

Step-by-step explanation:

Length of hypotenuse: 7^2+24^2=625. 625 square root=25

Thus, DE is 25.

Sin D= 24/25, so that is false.

Tan D= 24/7, so that is false.

Cos E= 24/25, so that is true

Sin E= 7/25, so that is false.

4 0
3 years ago
A rectangular floor space in a community center is 40 ft long and 32 ft wide. A volunteer is setting up chairs on the floor spac
pav-90 [236]
It is B because 40x32=1280 and 5x4=20 then divide 1280 by 20 and you get 64 but you can’t have 64 so you would need to only have 60 so the answer is B
6 0
3 years ago
Work out the height of a parallelogram with a base of 10m and an area of 60m2
noname [10]
Area formula of a parallelogram is
        A = base x height

Given are the
Area = 60 m² and base = 10 m

 Substitute the given:

60 = 10h  (divide by 10 to find value of h)
\frac{60}{10} = \frac{10h}{10}  (10 and 10 cancels out)

h = 6
The height of a parallelogram with a base of 10m and an area of 60m² is 6m

3 0
3 years ago
4W + 10 and solve if w = 10.​
scoray [572]

Answer:

50

Step-by-step explanation:

4w+10=4*10+10=40+10

40+10=50

6 0
3 years ago
Given the right angle triangle shown here, calculate:
charle [14.2K]

Answer:

see explanation

Step-by-step explanation:

(1)

(a)

sin(a) = \frac{opposite}{hypotenuse} = \frac{15}{17}

(b)

cos(a) = \frac{adjacent}{hypotenuse} = \frac{8}{17}

(c)

tan(a) = \frac{opposite}{adjacent} = \frac{15}{8}

----------------------------------------------------

(2)

(a)

sin(b) = \frac{opposite}{hypotenuse} = \frac{8}{17}

(b)

cos(b) = \frac{adjacent}{hypotenuse} = \frac{15}{17}

(c)

tan(b) = \frac{opposite}{adjacent} = \frac{8}{15}

5 0
3 years ago
Read 2 more answers
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