Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
The results of the arithmetic evaluations as given in the task content are; 40,42 and 62.
<h3>What are the results of the arithmetic evaluations?</h3>
The arithmetic operations above can be evaluated and simplified as follows;
(11-8)x3+7+27-3 = (3×3)+7+27-3 = 40.
(18÷3)+6+(14-8)x5 = (6)+6+(6)x5 = 42.
(11-7)x6+4+32-4 = (5×6) +4 +32-4 = 62.
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Answer:
12
Step-by-step explanation:
when + go to the other side it has to be -
w=16-4
=12
All you have to do is rotate the current dots, and bam.
Answer: Taxi driver has at most $10 to spend on the cab ride, he can travel at most 12.7 miles.
Step-by-step explanation:
A Taxi driver charges a flat rate = 7.25 dollars
taxi fare for 1 mile = 0.65 dollars
Suppose we consider Total money taxi driver can spend = 10 dollars
Let taxi driver travel x miles
Total charges = flat rate charge + taxi fare for each mile(distance) travelled
Find the value y = [?] + [?]x
suppose these two question marks indicate z1,z2
replace with y=10 and z1=1.75 and z2=0.65 values
Then y = [z1] + [z2]x
10 = 1.75 + 0.65(x)
0.65(x) = 10 - 1.75
0.65(x)= 8.25
x = 8.25/0.65
x = 12.7 miles
If Taxi driver has at most $10 to spend on the cab ride, he can travel at most 12.7 miles.
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