If the functions are inverses, then f(g(x)) = x.
A.
The functions are inverses of each other.
B. The domain of f(x) = x≠3. The domain of g(x) is x≠0.
The domain of f(g(x)) is (-∞, 0) ∪ (0, ∞).
The domain of g(f(x)) is (-∞, 3) ∪ (3, ∞).
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Where’s the cone? Is there a picture of a cone? I can’t really solve this, I’m sorry if I bother you
Answer:
1) 2x^4/343
2) 2x^6/225
3) 2x^12/25
4) 5x^20/16807
Step-by-step explanation:
Hope this helps!
