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sleet_krkn [62]
3 years ago
15

Write a complete balanced redox reaction, wherein electron(s) are transferred between Coenzyme Q and lipoic/dihydrolipoic acid,

that would occur spontaneously in the forward direction. Be sure to clearly indicate the states of all species on the reactant and product sides: ubiquinone or ubiquinol; lipoic acid or dihydrolipoic acid. g
Chemistry
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:

attached below

Explanation:

Attached below is the complete balanced redox reaction

Oxidation as seen in the first Redox equation is the addition of hydrogen or the loss of electrons

For The first reaction

The reactant = lipoic acid

product = dihydrolipoic acid

second reaction

The reactant ; ubiquinone

product ; ubiquinol

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The correct answer is Mercury

Explanation:

In a circular object or spherical object such as a planet, the diameter is calculated by drawing a straight line from one side of the sphere to the other. This measure is the double of the radius (distance from the center to any side). In the case of planets, these differ not only in properties but also in size, which makes them have different diameters.

For example, the diameter of Earth is approximately 12,700 km, while the diameter of Jupiter (the largest planet) is almost 143,000 km. In this context, the planet with a diameter that is approximately the same that the distance from one coast to the other in the U.S. is Mercury because the diameter of this planet is almost 4879 kilometers and the distance from the West coast to the East coast is approximately 4828 kilometers, although this distance varies depending on the location.

6 0
3 years ago
Does melting lose or gain energy
kompoz [17]
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4 0
3 years ago
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Choose all the answers that apply.
melamori03 [73]

Electrons have a negative charge and orbit around the nucleus, while protons have a positive charge and are found in the nucleus. Neutrons have no charge and are also found in the nucleus with protons.

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4 0
3 years ago
A truckload of apples weighs 2550 lbs. If 5 (exact) apples weigh 1250 g, how many apples are in the truck?
egoroff_w [7]

Answer:

There are 4,626 apples in the truck.

Explanation:

Mass of  5 apples = 1250

Mass of an apple = \frac{1250 g}{5}=250 g

Mass of apples in the truck = 2550 lbs

1 lbs = 453.592 g

2550 lbs=2550\times 453.592 g

Let the number of apples with mass of 2550 lbs be a.

a\times 250 g=2550\times 453.592 g

a=\frac{2550\times 453.592 g}{250 g}=4,626.63

4,626.63 ≈ 4,626

So, there are 4,626 apples in the truck.

3 0
2 years ago
The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.42×10−4s−1 at a certain temperature. What is t
Keith_Richards [23]

Answer:

a) Half life of the decomposition = 4951.1 s ≈ 4950 s

b) Time it will take for the concentration of SO₂Cl₂ to decrease to 25% of its initial concentration = 9900 s

c) If the initial concentration of SO₂Cl₂ is 1.00 M, time it will take for the concentration to decrease to 0.78 M is 1775s

d) If the initial concentration of SO₂Cl₂ is 0.150 M, the concentration of SO₂Cl₂ after 2.00×10² s is 0.146 M

e) If the initial concentration of SO₂Cl₂ is 0.150 M, the concentration of SO₂Cl₂ after 2.00×10² s is 0.1398 M

Explanation:

Let C₀ represent the initial concentration of SO₂Cl₂

And C be the concentration of SO₂Cl₂ at anytime.

a) Rate of a first order reaction is represented by

dC/dt = - KC

dC/C = - kdt

Integrating the left hand side from C₀ to C₀/2 and the right hand side from 0 to t(1/2) (where t(1/2) is the radioactive isotope's half life)

In [(C₀/2)/C₀] = - k t(1/2)

In (1/2) = - k t(1/2)

- In 2 = - k t(1/2)

t₍₁,₂₎ = (In 2)/k

t₍₁,₂₎ = (In 2)/(1.4 × 10⁻⁴)

t₍₁,₂₎ = 4951.1 s

b) dC/C = - kdt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

In (C/C₀) = - kt

C/C₀ = e⁻ᵏᵗ

C = C₀ e⁻ᵏᵗ

C = 25% of C₀ = 0.25C₀

0.25C₀ = C₀ e⁻ᵏᵗ

e⁻ᵏᵗ = 0.25

- kt = In 0.25

- kt = - 1.386

t = 1.386/(1.4 × 10⁻⁴) = 9900 s

c) C = C₀ e⁻ᵏᵗ

C = 0.78 M; C₀ = 1.00 M

0.78 = 1 e⁻ᵏᵗ

e⁻ᵏᵗ = 0.78

- kt = In 0.78

- kt = - 0.2485

t = 0.2485/(1.4 × 10⁻⁴) = 1775 s

d) C = C₀ e⁻ᵏᵗ

C₀ = 0.150 M, t = 2 × 10² s = 200 s

C = C₀ e⁻ᵏᵗ

e⁻ᵏᵗ = e^(-1.4 × 10⁻⁴ × 200) = 0.972

C = 0.15 × 0.972 = 0.146 M

e) C = C₀ e⁻ᵏᵗ

C₀ = 0.150 M, t = 5 × 10² s = 500 s

C = C₀ e⁻ᵏᵗ

e⁻ᵏᵗ = e^(-1.4 × 10⁻⁴ × 500) = 0.9324

C = 0.15 × 0.9324 = 0.1398 M

6 0
3 years ago
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