Gases tend to deviate from the ideal gas law at

Chemistry

1 answer:

MrRa [10]3 years ago

8 0

Answer:

Gases tend to deviate from ideal gas law at high pressures and low temperatures.

Explanation:

The main statements from molecular kinetic theory to describe an ideal gas is that 1) the gas particles occupy a neglictible fraction of the total volume of the gas, and 2) there is not force of attraction between gas particles.

HIgh pressure means that the gas particles will be forced closer to each other, making that the mean distance between the particles be realtively more important and their volume less neglictible. This is a violation the first assumption described above.

Since the temperature is directly related to the kinetic energy, and the latter with the movement of the particles (average speed), low temperatures lead to the molecules being less independent of each other, i.e. the forces between the molecules will count more . This fact constitutes a violation of the second principle established in the first paragraph.

In conclusion, high pressures and low temperatures tend to deviate gases from the ideal gas law.

You can read more about ideal and real gases behavior on brainly.com/question/12449772

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A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas i

ElenaW [278]

Answer:

470 °C

Explanation:

This looks like a case where we can use Charles’ Law:

$\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 20 L; T₁ = 100 °C

V₂ = 40 L; T₂ = ?

Calculations:

(a) Convert the temperature to kelvins

T₁ = (100 + 273.15) K = 373.15 K

(b) Calculate the new temperature

$\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}$