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Nastasia [14]
2 years ago
13

Please help! I don’t think my answer is right!

Chemistry
2 answers:
Ostrovityanka [42]2 years ago
4 0

Answer:

Thats right! Gj!

Explanation:

kirza4 [7]2 years ago
3 0

Answer:

You are actually correct!

Explanation:

<em>Base </em>turns Blue litmus to Red

<em>Acid </em>turns Red litmus to Blue

<em>Neuteral</em><em> </em><em>Solution </em><em>No </em><em>reaction!</em>

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Balance the equation below for the reaction between hydrogen and chlorine, using the smallest whole-number
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Which statement is true?
Amiraneli [1.4K]

Answer: c. Matter and energy are conserved in chemical reactions.

Explanation:

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8 0
2 years ago
What is the maximum amount of water (in grams) that can be removed from 15ml of toluene by the addition?
Nataly [62]

Complete Question

Magnesium sulfate forms a hydrate with the formula MgSO_4. 7H_20. What is the maximum amount of water (in grams) that can be removed from 15 ml of toluene by the addition of 200 mg of anhydrous magnesium sulfate? The molar mass of MgSO_4 is 120.4 g/mol; H20 = 18 g/mol.

Answer:

The value  is  z =  0.2093 \  g of  H_2O

Explanation:

From the question we are told that

   The volume of toluene is  V = 15 mL

    The mass of  anhydrous magnesium sulfate is  m =  200m g  = 200 *10^{-3} \  g

   The formula of the hydrate is   MgSO_4. 7H_20

    The molar mass of   MgSO_4  is  z =120.4 \ g/mol

From the formula given we see that

  1 mole of  Mg SO_4 wil remove  7 moles of H_2O to for the given formula

Hence

  120.4 g (1 mole) will remove  7 moles (7 * 18 g = 126 g  ) of  H_2O to for the given formula

Therefore 1 g of  Mg SO_4  x g  of  H_2O  

So

     x  =  \frac{x]126 *  1}{ 120.4 }

=>     x  =  1.0465 \  g

From our calculation we obtained that

  1 g of Mg SO_4 will remove  x  =  1.0465 \  g  of  H_2O  

Then  

   200 *10^{-3} \  g of Mg SO_4 will remove z g of  x  =  1.0465 \  g  of  H_2O  

So

   z =  200 *10^{-3} *  1.0465

=>z =  200 *10^{-3} *  1.0465

=>z =  0.2093 \  g of  H_2O  

6 0
3 years ago
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