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3 years ago

Cylinder capacity 4.25 L, cylinder diameter of 13 what is the height of the cylinder?

Mathematics

1 answer:

Musya8 [376]3 years ago

6 0

Answer:

Step-by-step explanation:

Capacity of cylinder =4.25L

So volume of the cylinder=4250

πr^2h=4250

3.14×6.5×6.5×h=4250

132.665h=4250

h=4250/132.665

h=32.035

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Tom bought one third pickles as many pickles as alexa. Together their pickles cost 56p. How many pickles did they each buy?

nordsb [41]

Answer:

Step-by-step explanation:

let pickle bought by alexa =x

then according to given condition ,

pickle bought by Tom= (1/3) of Alexa

pickle bought by Tom= (1/3) x

hence also given

totall pickle cost = Tom cost + alexa cost = 56p

(1/3)x+x=56

taking L.C.M

(4/3)x=56

x=56*3/4

x=42 p

so it means,

<h2>Alexa cost = x = 42p</h2><h2>Tom cost = (1/3)x= (1/3)*42 = 14 p</h2>

7 0

3 years ago

A ?<br> B?<br> C ?<br> D? <br> PLEASE

mario62 [17]

C that is the right answer

6 0

3 years ago

The Volume () of gas vanes inversely to the pressure (P). The volume of gas is 200 cm ^ 3 under pressure of 32 kg/cm^ 2 What wil

WITCHER [35]

Answer:

0.025 Kg/ cm²

Step-by-step explanation:

if two variables vary inversely, there is a negative relationship between both variables. the increase in one variable leads to a decrease in the other variable

the equation that represents inverse proportion :

$y = \frac{b}{x}$

where b = constant of proportionality

to determine the answer in this question :

1. determine constant of proportionality

200 = k / 32

k = 6400

2. Determine the amount of pressure using the constant of proportionality

256, 000 = 6400 / pressure

pressure = 6400 / 256, 000 = 0.025

4 0

3 years ago

Y=-0.72x + 7.7<br> Find y when x = 3.5.

OLEGan [10]

Answer:

y = 5.18

Step-by-step explanation:

replace x in the equation with 3.5

y = -0.72x + 7.7

y = -0.72(3.5) + 7.7

y = -2.52 + 7.7

y = 5.18

7 0

2 years ago

Read 2 more answers

At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa

11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 7 parts

r = number of success = fewer than 2

p = probability of success which in our question is % of defective

parts produced by one of the machine, i.e; 19%

<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

P(X < 2) = P(X = 0) + P(X = 1)

= $\binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}$

= $1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}$

= <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

8 0

3 years ago