To figure this out, replace the variables with their given values.
p(a/b) = p(.4/.5)
Then you divide!
.4/.5 = .8
Hope this helps!
Answer:
<h2>The box plot is the only display that can be used to show the variability of the data.</h2><h2>The median appears clearly on the box plot at the line within the box: 10.</h2>
Step-by-step explanation:
When we want to represent variability, we use a box plot instead of a dot plot, because the box plot allow us to observe the range of the data set, that is, the minium and the maximum value.
Remember that variability is about the spread of the dataset, and the range is a measure that can give a pretty good idea of it, shown by a box plot.
Therefore, the last hoice is correct.
On the other hand, according to the dot plot, the median is 10, because there are 13 total values, where the central value is 10.
Therefore, the second choice is correct.
Answer:
Step-by-step explanation:
Knowledge is knowing a tomato is a fruit, wisdom is not putting it in a fruit salad
Your time is too valuable to waste on those who don't deserve it
Never give up great things take time
Failure is not an acception
As a wise fish once said "Just Keep Swimming" the more u swim the closer you get to your goal.
Answer:
Perpendicular
Step-by-step explanation:
It is a symbol used for showing any two lines perpendicular to each other.
Answer:
Mean. It includes all data points.
Step-by-step explanation:
-We first need to calculate the mean, median and mode then compare our values:
#Mean:

#The median is the middlemost data point in a lsit data:
778,783,784,786,790,804,807,810,819,823
-Since our data points is an even number, the median number is calculated as:
![median=\frac{1}2}\sum{5^{th}+6^{th}}\\\\=0.5[790+804]\\\\=797.00](https://tex.z-dn.net/?f=median%3D%5Cfrac%7B1%7D2%7D%5Csum%7B5%5E%7Bth%7D%2B6%5E%7Bth%7D%7D%5C%5C%5C%5C%3D0.5%5B790%2B804%5D%5C%5C%5C%5C%3D797.00)
#Mode is the data point with the highest frequency:
-Since there's no number appearing more than once, our set has no mode.
#Since our data set has no outliers and is not a skewed distribution, the mean will be the best measure as it includes all data points