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3 years ago

Divide. (3 3/4)÷(−2 1/2) Enter your answer as a mixed number, in simplified form, in the box.

Mathematics

2 answers:

vekshin13 years ago

7 0

Answer:

1 1/2

Step-by-step explanation:

neonofarm [45]3 years ago

6 0

$3 \frac{3}{4} = \frac{15}{4}$

Because (4*3) + 3 = 15. Similary find the improper fraction for -2 1/2.

(15/4) / (-5/2) = -3/2

Convert -3/2 into a mixed fraction.

Therefore, -3/2 = -1 1/2.

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What is the median of this set of data: 10, 11, 12, 12, 15, 19, 20, 21, and 22? Express your answer as an integer.

Rama09 [41]

15, median is the number in the middle, (i.e. median of 3, 4, 8, 9, 10, is 8.)

4 0

3 years ago

Read 2 more answers

Find the LCM of the numbers using prime factorizations. 36,60

alexandr402 [8]

36=2*2*3*3=2²*3²
60=2*2*3*5=2²*3*5

LCM(36,60)=2*2*3*3*5=2²*3²*5=180

5 0

2 years ago

Item 10 Find the amount of time. I=$450, P=$2400, r=7.5%

Alex787 [66]

The answer is: "2.5 years" .
___________________________________________________
Note: I = P * r * t ; { " Interest = Principal * rate * time "} ;

→ Solve for "t" {"time", in years} ;

Divide each side of the equation by "{P * r}" ;
to isolate "t" on one side of the equation ;

→ I / (P * r) = {P * r * t) / (P * r} ;

to get: " I / (P * r) = t " ;

 ↔ t = I / (P * r) ;

Given: I = $450 ;

 P = $2400 ;

r = 7.5% = 7.5/100 = 0.075 ;

Plug in these values into the formula to solve for the time, "t" :

 → t = I / (P * r ) ;

= $450 / ($2400 * 0.075) ;

= $450 / ($2400 * 0.075) ;

= $450 / $180 ;

= $45 / $18 ;

= ($45 ÷ 9) / ($18 ÷ 9)

= $5 / $2 ;

= 2.5 ;

→ t = 2.5 years.
_______________________________________________________
The answer is: "2.5 years" .
_______________________________________________________

7 0

3 years ago

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

5 0

2 years ago

8x=9x−9 how many solutions

Alika [10]

Answer:

1 solution

Step-by-step explanation:

4 0

3 years ago