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RideAnS [48]
3 years ago
6

During the year, James had saved $500 for his summer vacation. By the second week, he has $375 left and by the seventh week, he

had $100 left. What was the rate of change from week 2 to week 7?
Mathematics
1 answer:
Lady bird [3.3K]3 years ago
6 0

Answer:

Amount used by the end of the second week= $500-$375

                                                                              =$125

Amount used by the end of the seventh week= $375-$100

                                                                             =$275

Total amount spent= $275+$125

                                 =$400

Rate of change= $ 500- $400

                          =$ 100

Step-by-step explanation: Hope this helps

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Answer:

$600

Step-by-step explanation:

A = P(1 + rt)

P is the Principal amount of money to be invested at an Interest Rate R% per period for t Number of Time Periods.

A= 5,000(1+ 0.08x1.5) = $5600

5 0
3 years ago
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3 years ago
Mrs. Grayson uses 2/ 3 of a dozen eggs to make a small chiffon cake. If she wants to bake 6 small chiffon cakes, how many dozen
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5 0
3 years ago
Read 2 more answers
Hattempt last question below, or select another question rest tenth of a percent Out of 270 racers who wanted the then, 243 comp
coldgirl [10]

Answer:

10%

Step-by-step explanation:

Given:

Total number of racers = 270

Number of racers completed the race = 243

Number of racers gave up = 20

Now,

The number of racers who did not complete the race

= Total number of racers - Number of racers completed the race

= 270 - 243

= 27

Therefore,

The percentage of racers who did not complete the race

= \frac{\textup{number of racers who did not complete}}{\textup{Total number of racers}}\times100\%

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= 10%

8 0
3 years ago
In 2013 your car was worth $12,500. In 2015 your car was worth $8,200.
N76 [4]

Answer:

A) V =12500[1-\frac{17.2 \times t}{100} ]

B)  V = 12500[1-\frac{19}{100} ]^{t}

Step-by-step explanation:

In two years i.e. from 2013 to 2015 the car value decreases from $12500 to $8200.

a) If the rate of decrease is constant and it is r% per year, then

8200 = 12500[1-\frac{r \times 2}{100}}]

⇒ r = 17.2%

Therefore, the value of the car is given by V =12500[1-\frac{17.2 \times t}{100} ], where, t is in years since 2013. (Answer)

b) If the rate of decrease is exponential and it is r%, then

8200 = 12500[1-\frac{r}{100} ]^{2}

⇒ r = 19%

Therefore, the value of the car is given by V = 12500[1-\frac{19}{100} ]^{t}, where, t is in years since 2013. (Answer)

3 0
3 years ago
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