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Masteriza [31]
2 years ago
9

Which sum or difference is equivalent to the following expression?

Mathematics
1 answer:
yawa3891 [41]2 years ago
5 0

Answer:

Which sum or difference is equivalent to the following expression?

5 minus 3 x over 5

A. 1 + three-fifths

B. 1 + 3 x over 5

C. 1 – 3 x over 5 *My answer

D. 25 – 15x

I took the test and I got it right

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F represents the fee (in dollars) for climbing d meters.
Grace [21]

Answer:

$12

Step-by-step explanation:

when d = 0,  F = 110

when d = 100, F = 110 + (0.12 x 100) = 122

when d = 200, F = 110 + (0.12 x 200) = 134

etc.

Therefore, increase in price for every 100 meters climbed = 134 - 122 = 122 - 110 = 12

3 0
2 years ago
6 Jenna bought n notebooks which cost 5 dollars each, and 3 pens which cost r dollars each. How much money did she spend?
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Find the volume of the solid. Round to the nearest tenth if necessary.
Vikki [24]
V= \frac{4}{3}  \pi  r^{3} or V=4.1888 r^{3}

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7 0
3 years ago
Write 5.2 in decimal fraction
Leya [2.2K]

Answer:

5 2/10

Step-by-step explanation:

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3 years ago
Read 2 more answers
Please help me answer this for a test im having trouble
Dimas [21]

Answer:

x + 1

y = 9

Step-by-step explanation:

In order to solve this question we need to represent "y "in terms of "x" in the first equation, and the plug in the "y" value in the first equation into the second one. Luckily for us in the first equation it already shows what "y" is equal to in terms of "x" (based on the first equation y = -x + 10). Now we just need to plug in the value that we got instead of "y" in the second equation, and so we get....

y = 7x + 2

(plug in the y value and get the following ….)

-x + 10 = 7x + 2

(now just solve the following equation)

-x + 10 + x = 7x + 2 + x

10 = 8x + 2

10 - 2 = 8x + 2 - 2

8 = 8x

8/8 = 8x/8

1 = x

Now that we know the value of "x", all we need to do now is substitute the value of "x" into any of the equations and we will get the value of "y". So we do the following.....

y =  7x + 2

y = 7(1) + 2

y = 7 + 2

y = 9

3 0
3 years ago
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