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Masteriza [31]
3 years ago
9

Which sum or difference is equivalent to the following expression?

Mathematics
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

Which sum or difference is equivalent to the following expression?

5 minus 3 x over 5

A. 1 + three-fifths

B. 1 + 3 x over 5

C. 1 – 3 x over 5 *My answer

D. 25 – 15x

I took the test and I got it right

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a tank is 1/6 full of gasoline. Of 8 litres are added it would be 1/4 full. how many litres does the tank hold
finlep [7]

The full tank has a volume of x litres.

The tank is 1/6 full, so it has (1/6)x litres of gasoline.

Now you add 8 litres. The tank now has (1/6)x + 8 litres.

It is now 1/4 full. 1/4 full means it has (1/4)x litres.

Therefore, (1/6)x + 8 must equal (1/4)x.

(1/6)x + 8 = (1/4)x

Multiply both sides by the LCD which is 12.

12(1/6)x + 12(8) = 12(1/4)x

2x + 96 = 3x

Subtract 2x from both sides.

96 = x

x = 96

Answer: The tank holds 96 litres.

6 0
4 years ago
Someone plz help me with these 2 problems! thank you
kompoz [17]
I am pretty sure the answer for the first one is x=-.498
4 0
4 years ago
What is 1/1 minus 7/12
Stolb23 [73]
5/12 because 1/1 is a whole, 1, so all you have to do is 1 - 7/12.
5 0
3 years ago
Read 2 more answers
Pls answer quickly
Blizzard [7]

Answer:

D) Carol scored the highest in math.

Step-by-step explanation:

Look at the chart and check each question.

A) history is her favorite subject - Wrong (This is about Marks Obtained, Not Favorite Subjects!)

B) carol scored more in physics than English - Wrong (In Physics, the score is 55 while in English, it is 65!)

C) Carol got the least marks in history - Wrong (History is at 48 while Biology is at 35!)

D) Carol scored the highest in math - Correct (The highest score is 80 which is Math!)

4 0
2 years ago
Find the length of the segment. round to the nearest tenth of a unit Q(-3,5) R(2,3)
Alborosie
\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
Q&({{ -3}}\quad ,&{{ 5}})\quad 
%  (c,d)
R&({{ 2}}\quad ,&{{ 3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
QR=\sqrt{[2-(-3)]^2+[3-5]^2}\implies QR=\sqrt{(2+3)^2+(3-5)^2}
\\\\\\
QR=\sqrt{5^2+(-2)^2}\implies QR=\sqrt{25+4}\implies QR=\sqrt{29}
4 0
4 years ago
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