Answer:
C
Step-by-step explanation:
If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18,
x=(m+9)/2
y=(2m+15)/2
z=(3m+18)/2
the average of x, y, and z
=(x+y+z)/3
=(m+9+2m+15+3m+18)/3
=(6m+42)/3
=2m+14
ans is C
Put the problem into a proportion to make it easier to solve.
32 x
=
16 100
You can use cross products to simplify this proportion. Multiply 32 by 100, and set that number equal to 16 *x.
Your equation should now look like this
3200=16x
You are trying to get the variable alone on one side, so you should divide both sides by 16.
If this is performed correctly, then your final answer should be
x=200.
It will take you 200 minutes (3 hours 20 mins) to read the pages that you promised Ms. Williams
I cant see it is blury try to take another picture
Here, 3x + 2y = 12
2x + 2y = 10
Subtract 2nd from 1st equation,
x = 2
Now, substitute in 2nd,
2(2) + 2y = 10
2y = 10 - 4
y = 6/2
y = 3
In short, Your Answer would be: (2, 3)
Hope this helps!
