You would substitute or plug in -5 wherever there is an x in the equation.
f(-5) = 6(-5) + 7
f(-5)= -30 + 7
f(-5) = -23
Circumference of circle = π x d
diameter = 3x2= 6m
3.14 x 6 = 18.84m (circumference)
Area of a circle = π x r x r
=3.14 x 3 x 3
=28.26m2 (area)
If all the angles add up to 90 degrees then you can set the equation 7x-9*2x=90
Simplify
9x-9=90
Plus 9 both sides
9x=99
Divide by 9 on both sides
X=11
The zero propperty because you are add any thing plus zero
Answer:
<h3>Daniel is correct</h3>
Step-by-step explanation:
Given the polynomial P(x) = x^2-3x-10
To check that the remainder is zero if divided by x - 5, we will first have to equate x - 5 to zero and get x;
x - 5 = 0
x = 5
Then find P(5)
P(5) = 5^2 - 3(5) - 10
P(5) = 25 - 15 - 10
P(5) = 25-25
P(5) = 0
<em>This shows that x - 5 is a factor of the polynomial since P(5) gave us zero according to the factor theorem</em>