All categories

3 years ago

Help with number one please. Thank you

Mathematics

1 answer:

hjlf3 years ago

8 0

Answer:

1) ray

Label here: $\overrightarrow{GF}$

Step-by-step explanation:

You see a part of a line. The is an endpoint, point G. Then you have point F, and it goes forever as shown by the arrowhead. This is a ray that starts at point G and goes in the direction of point F forever.

1) ray

Label here: $\overrightarrow{GF}$

You might be interested in

How do i solve for equations that have 2 variables

sergey [27]

Answer:

To solve for an equation with two variables, substitute a zero(0) into the other variable and find one variable.

Step-by-step explanation:

To solve for an equation with two variables, substitute a zero(0) into the other variable and find one variable.

Simple Example:

3x+3y=12

Substitute 0 as y,

3x+0=12

3x=12

12/3=4

x=4

Now substitute 4 into the main equation,

3(4)+3y=12

12+3y=12

-12 -12

3y=0

0/3=0

y=0

So the answer is

3(4)+3(0)=12

12=12

8 0

4 years ago

I do not understand this plz help me i am so confused

Mariulka [41]

That would be 3,300,200

6 0

3 years ago

What is a simlified form of x+3 over x^2-x-12 multiplied by x-4 over x^2-8x+16?

Vesnalui [34]

Answer:

$\large\boxed{\dfrac{x+3}{x^2-x-12}\cdot\dfrac{x-4}{x^2-8x+16}=\dfrac{1}{x^2-8x+16}}$

Step-by-step explanation:

$\dfrac{x+3}{x^2-x-12}\cdot\dfrac{x-4}{x^2-8x+16}=\dfrac{x+3}{x^2+3x-4x-12}\cdot\dfrac{x-4}{x^2-8x+16}\\\\=\dfrac{x+3}{x(x+3)-4(x+3)}\cdot\dfrac{x-4}{x^2-8x+16}=\dfrac{x+3}{(x+3)(x-4)}\cdot\dfrac{x-4}{x^2-8x+16}\\\\\text{cancel}\ (x+3)\ \text{and}\ (x-4)\\\\=\dfrac{1}{x^2-8x+16}$

6 0

3 years ago

Evaluate the expression. 2 • 15 – 7 + 4

weqwewe [10]

2*15-7+4
30-7+4
23+4
27

3 0

4 years ago

Someone help. Simplify: (1/a)^3

ankoles [38]

Answer:

1/a3 is the simplify expression for the equation

6 0

3 years ago