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pshichka [43]
3 years ago
15

Find the value of y: 8y(4y+24)

Mathematics
2 answers:
DENIUS [597]3 years ago
5 0
That’s what i found

Ray Of Light [21]3 years ago
3 0

Answer:

32y² + 192y

Step-by-step explanation:

First, we need to distribute 8y. This gets us 32y²+192y. I do not believe you can simplify that. I hope this helps!

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Find each angle measure
tigry1 [53]

Answer:

1=125

2=55

3=55

4=125

5=125

6=55

7=55

8=125

Step-by-step explanation:

5 0
2 years ago
The volume of a shampoo filled into a container is uniformly distributed between 370 and 385 milliliters. (a) What are the mean
Olenka [21]

Answer:

(a) mean = 377.5ml. standard deviation = 4.33

(b) 0.333

(c) 384.25 ml

Step-by-step explanation:

(a)The mean:

\mu = \frac{385 + 370}{2} = 377.5 ml

The standard deviation:

\sigma = \frac{385 - 370}{\sqrt{12}} = 4.33

(b)

P(x < 375) = \frac{375 - 370}{385 - 370} = \frac{1}{3} \approx 0.333

(c)P(x > m) = 0.95

\frac{m - 370}{385 - 370} = 0.95

m - 370 = 14.25

m = 384.25ml

So the volumn of shampoo should be 384.25ml to exceed 95% of containers.

7 0
3 years ago
How do i find the slant asymptope of x^3/(2(x+2)(x-4) aka x^3/(2x^2-8)
hram777 [196]
I’m really sorry I just don’t know I guess I’m. It smart enough try to look it up and wait for someone else to answer sorry again :(
6 0
2 years ago
What are the restrictions on the domain of g o h?
umka21 [38]

g(x) = \sqrt{x-4} and h(x)= 2x-8

g o h is a composition function

First we find g o h

g o h is g(h(x))

We plug in h(x) in g(x)

We replace x  with 2x-8 in g(x)

g(h(x)) = g (2x-8) = \sqrt{2x-8-4} = \sqrt{2x-12}

g(h(x)) = \sqrt{2x-12}

To find domain we look at the domain of h(x) first

Domain of h(x) is set of all real numbers

now we look at the domain of g(h(x))

Negative number inside the square root is imaginary. so we ignore negative number inside the square root

So to find domain we set 2x - 12 >=0   and solve for x

2x - 12 >=0

add both sides by 12

2x >= 12

divide both sides by 2

x > = 6



5 0
3 years ago
Read 2 more answers
The legs of a right triangle have lengths of 4 and 5 units. what is the length of the hypotenuse
vlabodo [156]
This question can be solved using the Pythagorean theorem. a^2 + b^2 = c^2 where a and b are the legs of the triangle and c is the hypotenuse.

4^2 + 5^2 = c^2
16 + 25 = c^2
41 = c^2
\sqrt{41} = c
So, c is approximately 6.403.
3 0
2 years ago
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