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mote1985 [20]
3 years ago
9

How is the periodic table organised?

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
7 0
Periodic table is organized on atomic number left to right and rows are periods columns are groups hope it helps
prisoha [69]3 years ago
5 0

The periodic table brings order to information about the chemical elements. The chemical elements are arranged in order of increasing atomic number. The horizontal rows are called periods and the vertical columns are called groups. Elements in the same group have similar chemical properties.

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if the gas pressure exerted by a gas at 45 degrees celsius in a volume of 1.944 ATM, how many moles of gas are present?​
Firdavs [7]
If the.pressure exerted by a gas at [math]25^{\circ} \mathrm{C}[/math] in a volume of 0.044 L is 3.81 atm, how many moles of gas are present
8 0
3 years ago
A bike rider approaches a hill with a speed of 8.5 m/s. The total mass of the bike and the rider is 85 kg. Find the kinetic ener
krek1111 [17]

KE=3070.625 J

Height = 3.686 m

<h3>Further explanation</h3>

mass of bike+rider=85 kg

velocity = 8.5 m/s

\tt KE=\dfrac{1}{2}mv^2\\\\KE=\dfrac{1}{2}\times 85\times 8.5^2\\\\KE=3070.625~J

Conservation of energy :

(KE+PE)₁ (downhill) = (KE+PE)₂ (up the hill)

PE₁=0⇒h=0

KE₂=0⇒v=0(stop), so equation becomes :

KE₁=PE₂

\tt KE_1=3070.625\\\\KE_1=mgh_2\\\\3070.625=85\times 9.8\times h\Rightarrow h=3.686~m

5 0
3 years ago
Determine the percentage composition (by mass) of oxygen in NH4NO3.
Brrunno [24]

Answer:

60%

Explanation:

M(NH4NO3) = 2*14 +4*1 +3*16 = 80 g/mol

M(3O) = 3*16 = 48 g/mol

(48/80) *100 % =60% oxygen by mass.

6 0
3 years ago
A sample of benzene was vaporized at 25◦C. When 37.5 kJ of heat was supplied, 95.0 g of the liquid benzene vaporized. What is th
grandymaker [24]

Answer:

Enthalpy of vaporization = 30.8 kj/mol

Explanation:

Given data:

Mass of benzene = 95.0 g

Heat evolved = 37.5 KJ

Enthalpy of vaporization = ?

Solution:

Molar mass of benzene = 78 g/mol

Number of moles = mass/ molar mass

Number of moles = 95 g/ 78 g/mol

Number of moles = 1.218 mol

Enthalpy of vaporization =  37.5 KJ/1.218 mol

Enthalpy of vaporization = 30.8 kj/mol

8 0
3 years ago
If exactly 59.6 g of nitrogen gas is needed to inflate your air bag to the
Inga [223]

Answer:

We need 92.3 grams of sodium azide

Explanation:

Step 1: Data given

Mass of nitrogen gas = 59.6 grams

Molar mass of nitrogen gas = 28.0 g/mol

Molar mass of sodium azide = 65.0 g/mol

Step 2: The balanced equation

2NaN3 → 2Na + 3N2

Step 3: Calculate moles nitrogen gas

Moles N2 = mass N2 / molar mass N2

Moles N2 = 59.6 grams/ 28.0 g/mol

Moles N2 = 2.13 moles

Step 4: Calculate moles NaN3

for 2 moles NaN3 we'll have 2 moles Na and 3  moles N2

For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3

Step 5: Calculate mass NaN3

Mass NaN3 = Moles NaN3 * molar mass NaN3

Mass NaN3 = 1.42 moles * 65.0 g/mol

Mass NaN3 = 92.3 grams

We need 92.3 grams of sodium azide

7 0
3 years ago
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