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lilavasa [31]
4 years ago
9

What procedure could a student use to examine an intensive property of a rectangular block of wood

Chemistry
1 answer:
photoshop1234 [79]4 years ago
8 0

An intensive property does not change when you take away some of the sample. The procedures that a student could use to examine the intensive property of a rectangular block of wood are the hardness, color, density and molecular weight.

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The introduction of synthetic fertilizers and chemical pesticides to farming date back to the __________
laiz [17]

Answer:

Humans started to use pesticides dating back to before 2000 BC.

Hope this helps ^-^

Explanation:

4 0
4 years ago
Hydrogen is in Group 1A of the periodic table, known as the alkali metals, although it obviously isn't a metal. What is the reas
maria [59]
The answer is a because it's electron configuration is ns1
7 0
3 years ago
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How do the isotopes of an element differ? How are they the same?
OverLord2011 [107]

Answer:

They differ by their atomic mass and have same proton number.

Explanation:

Isotopes are atoms of the same element with the same proton or atomic number but with different atomic masses.

7 0
3 years ago
When 3.24 g of a nonelectrolyte solute is dissolved in water to make 955 mL of solution at 22 °C, the solution exerts an osmotic
attashe74 [19]

Answer:

The molar concentration is 0.0529 M

We have 0.0505 moles solute

The molar mass of the solute is 64.16 g/mol

Explanation:

Step 1: Data given

Mass of the  nonelectrolyte solute = 3.24 grams

Volume of water = 955 mL

Temperature = 22 °C = 295 K

Osmotic pressure = 973 torr = 973 / 760 = 1.28026 atm

Step 2: Calculate mass water

Mass water = 955 mL * 1g/mL

Mass water = 955 grams = 0.955 kg

Step 3: Calculate the molar concentration

π = i*M*R*T

⇒with π = the osmotic pressure = 1.28026 atm

⇒with i = the van't Hoff factor = 1

⇒with M = the molar concentration

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 295 K

M = 1.28026 / (0.08206*295)

M = 0.0529 M

Step 4: Calculate moles solute

Molar concentration = moles / volume

Moles solute = Molar concentration * volume

Moles solute = 0.0529 M * 0.955 L

Moles solute = 0.0505 moles

Step 5: Calculate molar mass

Molar mass = mass / moles

Molar mass = 3.24 grams / 0.0505 moles

Molar mass = 64.16 g/mol

The molar concentration is 0.0529 M

We have 0.0505 moles solute

The molar mass of the solute is 64.16 g/mol

4 0
3 years ago
. An inflated balloon has a volume of 6.0 L at sea level (1.0 atm) and is allowed to ascend in altitude until the pressure is 0.
Tju [1.3M]

Answer:

The answer to your question is Volume = 11.4 L

Explanation:

Data

Volume 1 = V1 = 6 L

Pressure 1 = P1 = 1 atm

Temperature 1 = T1 = 22°C

Volume 2 = V2 = ?

Pressure 2 = 0.45 atm

Temperature 2 = -21°C

Process

1.- Convert temperature (°C) to °K

T1 = 273 + 22 = 295°K

T2 = 273 + (-21) = 252°K

2.- Use the combined gas law to solve this problem

                   P1V1 / T1 = P2V2 / T2

-Solve for V2

                   V2 = P1V1T2 / T1P2

-Substitution

                   V2 = (6)(1)(252) / (295)(0.45)

- Simplification

                   V2 = 1512 / 132.75

- Result

                   V2 = 11.38 L

3 0
3 years ago
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