Answer:
Explanation:
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In this case, given the Henderson-Hasselbach equation, it is possible for us to compute the pH by firstly computing the concentration of the acid and the conjugate base; for this purpose we assume that the volume of the total solution is 0.025 L and the molar mass of the sodium base is 234 - 1 + 23 = 256 g/mol as one H is replaced by the Na:
And the concentrations are:
Then, considering that the Ka of this acid is 2.5x10⁻⁵, we obtain for the pH:
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Answer:
c. 0.750 atm .
Explanation:
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In this case, since the two vessels have different volume, we can see that the gas is initially at 3.00 atm into the 1.00-L vessel, but next, it is allowed to move towards the 3.00-L vessel, meaning that the final volume wherein the gas is located, is 4.00 L; therefore, we use the Boyle's law to compute the final pressure:
Therefore the answer is c. 0.750 atm .
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Answer:
The answer is
<h2>2 cm/year</h2>Explanation:
To find the rate in cm/year we must first convert 200 m into cm
1 m = 100 cm
if 1 m = 100 cm
Then 200 m = 200 × 100 = 20 ,000 cm
So the rate is
<h2><u>Reduce the fraction with 10,000</u>
We have the final answer as
<h3>2 cm/year</h3>Hope this helps you