Answer:
32.4 K
Explanation:
From the given parameters;
Initial pressure P1= 50.0 mmHg
Initial temperature T1= 540K
Final Temperature T2 = ?????
Final pressure P2=3 mmHg
Now using this relationship;
P1/T1 = P2/T2
We have; P1T2= P2T1
Hence;
T2= P2T1/P1
T2= 3 ×540/50.0
T2= 32.4 K
Answer : The specify the l and ml values for n = 4 are:
At l = 0, 
At l = 1, 
At l = 2, 
At l = 3, 
Explanation:
There are 4 quantum numbers :
Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....
Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from 
. When l = 2, the value of 
will be -2, -1, 0, +1, +2.
Spin Quantum number : It describes the direction of electron spin. This is represented as 
The value of this is 
for upward spin and 
for downward spin.
As we are given, n = 4 then the value of l and ml are,
l = 0, 1, 2, 3
At l = 0,
At l = 1,
At l = 2,
At l = 3,
Liquid
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You must add 45 mL of the 80 % alcohol to the 30 % alcohol to get a 35 % solution.
You can use a modified dilution formula to calculate the volume of 80 % alcohol
V1×C1 + V2×C2 = V3×C3
Let the volume of 80 % mixture 1 = <em>x</em> mL. Then the volume of the final 35 % mixture 3 = (405 + <em>x</em> ) mL
(<em>x</em> mL×80 % alc) + (405 mL×30 % alc) = (405 + <em>x</em>)mL × 35 % alc
80x + 12 150 = 14 175 + 35 x
45x = 2025
x = 2025/45 = 45
Answer: What conclusion can be drawn from the statement that an element has high ionization energy and small atomic size? The element is most likely from Group 1A or 2A and in period 1 or 2. Describe how the atomic radius of an element is related to metallic character.
Explanation:
