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KonstantinChe [14]
3 years ago
13

Consider the following mechanism: O3 => O2 + O NO + O => NO2 What is the role of O2? A. intermediate B. catalyst C. reacta

nt D. product
Chemistry
1 answer:
Daniel [21]3 years ago
5 0

Answer:

The correct answer is option D.

Explanation:

Step 1: O_3\rightarrow O_2+O

Step 2: NO+O\rightarrow NO_2

Overall reaction can be determined  by adding all the reactions of mechanism:

O_3+NO\rightarrow O_2+NO_2

Reactants in an overall reaction = O_3\& NO

Products in an overall reaction = O_2\& NO_2

According to question , the role of oxygen gas is product.

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Answer:

NVIDIA GeForce RTX 3080 10GB GDDR6X PCI Express 4.0 Graphics Card

Explanation:

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3 years ago
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A solution was prepared by dissolving 0.800 g of sulfur S8, in 100.0 g of acetic acid, HC2H3O2. Calculate the freezing point and
sammy [17]

<u>Answer:</u> The freezing point of solution is 16.5°C and the boiling point of solution is 118.2°C

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute (S_8) = 0.800 g

M_{solute} = Molar mass of solute (S-8) = 256.52 g/mol

W_{solvent} = Mass of solvent (acetic acid) = 100.0 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{0.800\times 1000}{256.52\times 100.0}\\\\\text{Molality of solution}=0.0312m

  • <u>Calculation for freezing point of solution:</u>

Depression in freezing point is defined as the difference in the freezing point of water and freezing point of solution.

\Delta T_f=\text{freezing point of acetic acid}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

or,

\text{Freezing point of acetic acid}-\text{Freezing point of solution}=iK_fm

where,

Freezing point of acetic acid = 16.6°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal freezing point depression constant = 3.59°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

16.6^oC-\text{freezing point of solution}=1\times 3.59^oC/m\times 0.0312m\\\\\text{Freezing point of solution}=16.5^oC

Hence, the freezing point of solution is 16.5°C

  • <u>Calculation for boiling point of solution:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of acetic acid}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

or,

\text{Boiling point of solution}-\text{Boiling point of acetic acid}=iK_fm

where,

Boiling point of acetic acid = 118.1°C

i = Vant hoff factor = 1 (for non-electrolyte)

K_f = molal boiling point elevation constant = 3.08°C/m

m = molality of solution = 0.0312 m

Putting values in above equation, we get:

\text{Boiling point of solution}-118.1^oC=1\times 3.08^oC/m\times 0.0312m\\\\\text{Boiling point of solution}=118.2^oC

Hence, the boiling point of solution is 118.2°C

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3 years ago
A container holds 6.4 moles of gas. Hydrogen gas makes up 25% of the total moles in the container. If the total pressure is 1.24
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  The   partial  pressure of hydrogen is 0.31  atm

calculation

find the number of  hydrogen   moles the container, that is

25/100  x 6.4  =1.6 moles of hydrogen

find the  partial pressure for hydrogen  in 1.6 moles

that is   6.4  moles=  1.24 atm
            1.6  moles= ?

by  cross  multiplication

1.6moles  x1.24  atm/ 6.4 moles=  0.31 atm
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45 g  Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.

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Explanation:

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