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KonstantinChe [14]
3 years ago
13

Consider the following mechanism: O3 => O2 + O NO + O => NO2 What is the role of O2? A. intermediate B. catalyst C. reacta

nt D. product
Chemistry
1 answer:
Daniel [21]3 years ago
5 0

Answer:

The correct answer is option D.

Explanation:

Step 1: O_3\rightarrow O_2+O

Step 2: NO+O\rightarrow NO_2

Overall reaction can be determined  by adding all the reactions of mechanism:

O_3+NO\rightarrow O_2+NO_2

Reactants in an overall reaction = O_3\& NO

Products in an overall reaction = O_2\& NO_2

According to question , the role of oxygen gas is product.

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I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a
matrenka [14]

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/  0.0821 atm.L/mol.K × 3 mol

T= 125  /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

4 0
3 years ago
PLEASE HELP!!!!!! WILL GIVE BRAINLIEST!!!! IT'S SUPER EASY
Nana76 [90]

the primary consumer in those photos would be C

6 0
3 years ago
In animal cells, DNA is organized in the _______.
Luda [366]
The answer is: Nucleus (same as in plant cells)
5 0
4 years ago
Read 2 more answers
15.630 g milk chocolate bar ks found to contain 9.815g of sugar. how many milligrams of sugar does the bar contain?
sleet_krkn [62]
Well there are 1,000 milligrams in 1 gram so 9.815 grams of sugar is equivalent to 9,815 milligrams of sugar. So a bar of milk chocolate contains 9,815 milligrams of sugar.
3 0
3 years ago
Read 2 more answers
A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm  ; Final Volume = 1.8 L ; Final pressure = 0.73 atm  

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T_2 ),

P_1V_1 / T_1 = P_2V_2 / T_2,

T_2 = P_2V_2T_1 / P_1V_1,

T_2 = 0.73 atm * 1.8 L * 298.15 K / 1 atm * 1.2 L = ( 0.73 * 1.8 * 298.15 / 1 * 1.2 ) K = 326.47425 K,

T_2 = 326.47425 K = 53.32425 C

7 0
3 years ago
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