Answer:
The percentage of the number of marching band members increased by 16% this year.
Step-by-step explanation:
x 100% = 16%
56 is 16% of 350
What is the perimeter of this triangle?
1 answer:
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Answer:
Area of Trapezoid is 39 unit²
Step-by-step explanation:
Given as :
For A Trapezoid
The measure of base side 1 = = 10 unit
The measure of base side 2 = = 16 unit
The height of the Trapezoid = h = 3 unit
Let The Area of Trapezoid = A square unit
<u>Now, From Formula</u>
Area of Trapezoid = × (sum of opposite base) × height
I.e A = × (
+
) × h
Or, A = × (10 unit + 16 unit) × 3 unit
Or, A = × (26 unit) × 3 unit
Or, A = × 78 unit²
Or, A = unit²
I.e A = 39 unit²
So, The Area of Trapezoid = A = 39 unit²
Hence, The Area of Trapezoid is 39 unit² . Answer
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Solve the trigonometric equation:
Restriction for the solution:
Square both sides of (i):
![\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}](https://tex.z-dn.net/?f=%5Cmathsf%7B%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2%5Ccdot%20%281-sin%5E2%5C%2Cx%29-sin%5C%2Cx%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2-2%5C%2Csin%5E2%5C%2Cx-sin%5C%2Cx%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7B-%5C%2C%5Cdfrac%7Bsin%5C%2Cx%7D%7Bcos%5E2%5C%2Cx%7D%5Ccdot%20%5Cleft%5B2%5C%2Csin%5E2%5C%2Cx%2Bsin%5C%2Cx-2%20%5Cright%5D%3D0%7D%5C%5C%5C%5C%5C%5C%20%5Cmathsf%7Bsin%5C%2Cx%5Ccdot%20%5Cleft%5B2%5C%2Csin%5E2%5C%2Cx%2Bsin%5C%2Cx-2%20%5Cright%5D%3D0%7D)
Let
So the equation becomes
Solving the quadratic equation:
You can discard the negative value for t. So the solution for (ii) is
Substitute back for t = sin x. Remember the restriction for x:
where k is an integer.
I hope this helps. =)
——————————
Solve the trigonometric equation:
Restriction for the solution:
Square both sides of (i):
Let
So the equation becomes
Solving the quadratic equation:
You can discard the negative value for t. So the solution for (ii) is
Substitute back for t = sin x. Remember the restriction for x:
where k is an integer.
I hope this helps. =)