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WARRIOR [948]
3 years ago
14

Technician A says that the traction control system was developed to prevent the drive wheels from slipping while the vehicle is

being decelerated when coming to a stop. Technician B says that above a manufacturer-specified speed, the traction control system deactivates. Who is correct
A. Technician A Only
B. Technician B Only
C. Bpth A and B
D. Neither A nor B
Physics
2 answers:
dmitriy555 [2]3 years ago
8 0

Answer:

The correct option is;

B. Technician B Only

Explanation:

The traction control system (TCS) also known as ASR or drive slippage regulation is a safety feature of the vehicle stability control present in automobiles. TCS is brought into play at the instant there is a mismatch between the throttling and the torque of the engine to the condition of the surface of the road.

TCS is functional to a speed specified by the automobile manufacturer above which the Electronic Brake Control Module (EBCM) deactivates the wheels will not loose traction when the acceleration is further increased

An Anti-lock Braking System (ABS) is meant to prevent skidding.

mihalych1998 [28]3 years ago
3 0

Answer:

Option B.

Technician B Only is correct

Explanation:

Traction Control systems are systems in a vehicle that are deigned to  optimize grip and stability of the car on the road during acceleration by measuring wheel rotation.

Traction systems are designed to work during acceleration, not deceleration. this makes Technician A wrong.

Traction control systems are pretty much  active up to a manufacturer-specified speed. Above that speed, the  traction control is deactivated by the electronic brake control module because further acceleration is unlikely to cause the wheels to lose traction. This makes Technician B correct

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if the intensity of a person's voice is 4.6 x 10^-7 w/m^2 at a distance of 2.0 m, how much sound power does that person generate
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The sound power the person generated is 2.313 \times 10^{-5} \ W.

<h3>Area of the sound wave</h3>

The area of the sound wave is calculated as follows;

A = 4\pi r^2\\\\A = 4 \pi \times (2)^2\\\\A = 50.272 \ m^2

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The sound power the person generated is calculated as follows;

P = I A\\\\P = 4.6\times 10^{-7} \ W/m^2 \ \ \times \ \ 50.272 \ m^2\\\\P = 2.313 \times 10^{-5} \ W

Learn more about intensity of sound here: brainly.com/question/4431819

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