Answer:
Explanation:
The diagram has a fairly simple explanation. In the top diagram, the space between the particle is increasing. That means that acceleration is increasing. The bottom diagram shows just the opposite. The particle starts off making large "distances" between where the particle is recorded and then the distances between recordings lessens and the particle is slowing down.
Rule: the greater the "distance" between dot positions, the greater the acceleration, because the speed is large.
Top diagram: increasing distance between dots = larger speed. The distance becomes greater as the particle moves to the right.
Bottom diagram: starts off large and decreases as we move from left to right = - acceleration.
Beta Carotene is the reason why a carrot is orange. Carotene is a color pigment that is found in large quantities in carrots and it has health benefits as well. The main health benefit of carotene is that our body converts it into vitamin A which is essential.
Answer:
Explanation:
From, the given information: we are not given any value for the mass, the proportionality constant and the distance
Assuming that:
the mass = 5 kg and the proportionality constant = 50 kg
the distance of the mass above the ground x(t) = 1000 m
Let's recall that:
![v(t) = \dfrac{mg}{b}+ (v_o - \dfrac{mg}{b})^e^{-bt/m}](https://tex.z-dn.net/?f=v%28t%29%20%3D%20%5Cdfrac%7Bmg%7D%7Bb%7D%2B%20%28v_o%20-%20%5Cdfrac%7Bmg%7D%7Bb%7D%29%5Ee%5E%7B-bt%2Fm%7D)
Similarly, The equation of mption:
![x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})](https://tex.z-dn.net/?f=x%28t%29%20%3D%20%5Cdfrac%7Bmg%7D%7Bb%7Dt%2B%5Cdfrac%7Bm%7D%7Bb%7D%20%28v_o%20-%20%5Cdfrac%7Bmg%7D%7Bb%7D%29%20%281-e%5E%7B-bt%2Fm%7D%29)
replacing our assumed values:
where ![v_=0 \ and \ g= 9.81](https://tex.z-dn.net/?f=v_%3D0%20%5C%20and%20%5C%20g%3D%209.81)
![x(t) = \dfrac{5 \times 9.81}{50}t+\dfrac{5}{50} (0 - \dfrac{(5)(9.81)}{50}) (1-e^{-(50)t/5})](https://tex.z-dn.net/?f=x%28t%29%20%3D%20%5Cdfrac%7B5%20%5Ctimes%209.81%7D%7B50%7Dt%2B%5Cdfrac%7B5%7D%7B50%7D%20%280%20-%20%5Cdfrac%7B%285%29%289.81%29%7D%7B50%7D%29%20%281-e%5E%7B-%2850%29t%2F5%7D%29)
![x(t) = 0.981t+0.1 (0 - 0.981) (1-e^{-(10)t}) \ m](https://tex.z-dn.net/?f=x%28t%29%20%3D%200.981t%2B0.1%20%280%20-%200.981%29%20%281-e%5E%7B-%2810%29t%7D%29%20%5C%20m)
![\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%28t%29%20%3D%200.981t-0.981%281-e%5E%7B-%2810%29t%7D%29%20%5C%20m%7D)
So, when the object hits the ground when x(t) = 1000
Then from above derived equation:
![\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}](https://tex.z-dn.net/?f=%5Cmathbf%7Bx%28t%29%20%3D%200.981t-0.981%281-e%5E%7B-%2810%29t%7D%29%20%5C%20m%7D)
![1000= 0.981t-0.981(1-e^{-(10)t}) \ m](https://tex.z-dn.net/?f=1000%3D%200.981t-0.981%281-e%5E%7B-%2810%29t%7D%29%20%5C%20m)
By diregarding ![e^{-(10)t} \ m](https://tex.z-dn.net/?f=e%5E%7B-%2810%29t%7D%20%5C%20m)
![1000= 0.981t-0.981](https://tex.z-dn.net/?f=1000%3D%200.981t-0.981)
1000 + 0.981 = 0.981 t
1000.981 = 0.981 t
t = 1000.981/0.981
t = 1020.36 sec
M is 3kg
r is 2m
v is 6m/s
Fc = mv^2 / r
Fc = (3x6^2)/2 =54
a = v^2/r
a = 6^2 /2 = 18
Answer:
Bok.............................