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Rashid [163]
3 years ago
15

When capacitors are connected in parallel, they have the same:.

Physics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

THEY HAVE THE SAME VOLTAGE

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Un bombero alejado d = 31.0 m de un edificio en llamas dirige un chorro de agua desde una manguera contra incendios a nivel del
Mila [183]

Answer:

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

Explanation:

El chorro de agua exhibe un movimiento parabólico, dado que este tiene una inclinación inicial y la única aceleración es debida a la gravitación terrestre. Las ecuaciones cinemáticas que modelan el fenómeno son:

Distancia horizontal (en metros)

x = x_{o} + v_{o}\cdot t \cdot \cos \theta

Donde:

x_{o} - Posición horizontal inicial, medida en metros.

t - Tiempo, medido en segundos.

v_{o} - Velocidad inicial, medida en metros por segundo.

\theta - Angulo de inclinación del chorro de agua, medido en grados sexagesimales.

Distancia vertical (en metros)

y = y_{o} + v_{o}\cdot t \cdot \sin \theta + \frac{1}{2}\cdot g \cdot t^{2}

Donde:

y_{o} - Posición vertical inicial, medida en metros.

g - Constante gravitacional, medida en metros por segundo al cuadrado.

Partiendo de la primera ecuación, se despeja el tiempo:

t = \frac{x - x_{o}}{v_{o}\cdot \cos \theta}

Si x = 31\,m, x_{o} = 0\,m, v_{o} = 40\,\frac{m}{s} and \theta = 33^{\circ}, entonces:

t = \frac{31\,m-0\,m}{\left(40\,\frac{m}{s} \right)\cdot \cos 33^{\circ}}

t = 0.924\,s

La altura máxima se calcula por sustitución directa de términos en la segunda ecuación. Si y_{o} = 0\,m, v_{o} = 40\,\frac{m}{s}, t = 0.924\,s y g = -9.807\,\frac{m}{s^{2}}, entonces:

y = 0\,m + \left(40\,\frac{m}{s} \right)\cdot (0.924\,s)\cdot \sin 33^{\circ} + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right) \cdot (0.924\,s)^{2}

y = 15.943\,m

El chorro golpea el edificio a una altura de 15.943 metros con respecto al suelo.

3 0
3 years ago
Beams of high-speed protons can be produced in "guns" using electric fields to accelerate the protons. A certain gun has an elec
Natasha2012 [34]

Answer: v = 2.75 * 10^7 m/s

Explanation: Since the electric field is a uniform one and the distance is small, the motion of the electron is of a constant acceleration, hence newton's laws of motion is applicable.

From the question

E=strength of electric field = 214N/c

q=magnitude of an electronic charge = 1.609* 10^-16c

m= mass of an electronic charge = 9.11*10^-31kg

v = velocity of electron.

S= distance covered = 1cm = 0.01m

a = acceleration of electron.

F = ma but F=Eq

Eq = ma.

a = Eq/m

a = 214 * 1.609*10^-16/ 9.11 * 10^-31

a = 344.32 * 10^-16/ 9.11 * 10 ^-31

a = 3. 779* 10^16 m/s²

Before the electron is accelerated, they are always not moving, hence initial velocity (u) = 0.

By using the equation of motion, we have

v² = u² + 2aS

But u = 0

v² = 2aS

v²= 2* 3.779*10^16 * 0.01

v² = 7.558 * 10^14

v = √7.558 * 10^14

v = 2.75 * 10^7 m/s.

6 0
3 years ago
A 600 g model rocket is on a cart that is rolling to the right at a speed of 4.0 m/s. The rocket engine, when it is fired, exert
murzikaleks [220]

Answer:

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

Explanation:

Step 1: Data given

mass of the rocket = 600 grams

speed = 4.0 m/s

Step 2: Calculate weight

Fw = mg

with Fw = the weight (in Newton)

with m = the mass (in kg)

with g = the acceleration due to gravity (9.81 m/s²).

Fw = (0.600 kg)(9.81 m/s²)  = 5.886 N

Step 3: Calculate force available to provide acceleration

The rocket engine, when it is fired, exerts a 8.0 AND vertical thrust on the rocket.

5.886 N of that force will be used to counter the rocket's weight, leaving 2.114 N of force available to provide acceleration.  

Step 4: Calculate the rocket's upward acceleration:

Fnet = m*a

With Fnet = the net force (the force that remains after the rocket's weight is compensated)

with a = the rocket's acceleration (in m/s²)

2.114 N = (0.600 kg)*a

a = 3.52 m/s²  = the rocket's upward acceleration

Step 5: Calculate how long it will take to rise 20 meters into the air.

Δy = v0*t + 1/2 at²

with v0 = 0m/s

Δy = 1/2 at²

20 m = 1/2(3.52)t²

20 m = (1.76 m/s²)t²

11.36 = t²

t = 3.37 s

This means the rocket will take 3.37 seconds to reach the hoop.  It should be launched when the cart is 3.37 seconds away from being directly beneath the hoop.  

Step 6: Calculate the distance

v = Δx / t

4.0 m/s = Δx / 3.37 s

Δx = 13.48 m

The rocket should be launched when the cart is 13.48m away from a point directly below the hoop.

8 0
4 years ago
How Do The Northern Lights work?
pishuonlain [190]

1.) Electrons go back into like a lower energy level then would be release a thing called a photon light.

2.) I'm not sure on the correct numbers exactly but if I remember correctly around 70-80 percent is nitrogen, around 20-25 is percent oxygen, 0.9 percent is argon, and 0.1 percent other gases. 

3.) Glass is made from sand at least that's one popular element of making sand. one gathered, they are put into a high temperature and would soon make glass coming out of it within time.

6 0
3 years ago
Click through the images and select the model that best shows how J.J. Thomson envisioned the atom.
Alexandra [31]

Answer:

The first one with the big plus in the middle and negatively charged electrons around.

Explanation:

7 0
3 years ago
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