10)
60in=60in × (1ft/12in) = 5ft
30in= 30in × (1ft/12in) = 2.5ft
12in = 12in × (1ft/12in) = 1ft
answer is = 5ft × 2.5ft× 1ft =12.5 ft^3 = a
11)
dozen = 12 hammers
12 hammers = 20 pounds
therefore 1 hammer= 20/12 = 1.6666 lb
21 hammers ×1.666 = 35 = c
12)
convert qt to gal
600 gal × 4 qt/gal = 2400 qt
2400 qt ÷ 120 qt/min
=20 min = d
13)
Carla is 12
rob is 12+5= 17
cousin is 12-7 = 5
12+17+5= 34 =a
15)
convert 60ft into yards
60 ft × 0.333 yd/ft =20 yd
diameter = 20 yd
area of circle = (pi/4)×d^2
(pi/4)×20^2= 314.16 = b
Answer:
- x = 37
- DG = 22
- AG = 44
- AD = 66
Step-by-step explanation:
We presume your "centroid ratio theorem" tells you that AG = 2·DG, so ...
(x+7) = 2(x -15)
x + 7 = 2x - 30 . . . . eliminate parentheses
37 = x . . . . . . . . . . .add 30-x
Then AG = 37+7 = 44
and DG = 37-15 = 22.
Of course, AD = AG +GD = 44 +22 = 66
Answer:
226.084 sq.m.
Step-by-step explanation:
Radius of circle = 18.6 cm
Area of sector = 
Area of sector = 
Area of sector = 
Area of triangle = 
a = OA = radius = 18.6 cm
b = OB = radius = 18.6 cm
x =123 °
Substitute the values in the formula
Area of triangle = 
Area of triangle = 
So, Area of shaded region = Area of sector - Area of triangle
=
=
Hence the area of the shaded region is 226.084 sq.m.
Answer: 17/60
Step-by-step explanation:
Change all of the fractions to have a common denominator:
LCM of 10, 12, 15 is 60
You get 12/60, 25/60, and 54/60.
54/60 is what he had at the start, and so you can just subtract what he gave away
54/60-12/60=42/60
42/60-25/60=17/60
17 is a prime number so you cannot simplify the fraction