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hodyreva [135]
2 years ago
13

1/2 (2n + 6) simply the answer and show work

Mathematics
1 answer:
Evgesh-ka [11]2 years ago
7 0

Answer:

The answer is n + 3.

Step-by-step explanation:

1) Simplify.

\frac{2n + 6}{2}

2) Factor out the common term 2.

\frac{2( n+ 3)}{2}

3) Cancle 2.

n + 3

<u>Th</u><u>e</u><u>refor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>n</u><u> </u><u>+</u><u> </u><u>3</u><u>.</u>

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Evaluate twenty-five minus three x for x equals zero, one, two, three, and four. Which of the following correctly describes the
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Answer:

You take turns plugging in each number for your answers. I’ll list them below.

6(0) - (0)2 = 0

6(1) - (1)2 = 4

6(2) - (2)2 = 8

6(3) - (3)2 = 12

6(4) - (4)2 = 16

6(5) - (5)2 = 20

6(6) - (6)2 = 24

The pattern I’ve noticed is every time you increase the value from the previous meaning for x, the solution increases by 4. I hope this helps and let me know if I’m right.

7 0
3 years ago
Read 2 more answers
Help me with 16,17,18,and 19 please simpl
mixas84 [53]

Answer:

Ques 16)

We have to simplify the expression:

\dfrac{t^2}{t^2+3t-18}-(\dfrac{5t}{t^2+3t-18}-\dfrac{t-3}{t^2+3t-18})\\   \\=\dfrac{t^2}{t^2+3t-18}-(\dfrac{4t+3}{t^2+3t-18})\\  \\=\dfrac{t^2-4t-3}{t^2+3t+18}

Ques 17)

\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{2w^2-9w+4}{(2w^2+9w-5)(w^2-w-12)}\\  \\=\dfrac{3w^2+7w-7}{w^2+8w+15}+\dfrac{(2w-1)(w-4)}{(2w-1)(w+5)(w+3)(w-4)}\\\\=\dfrac{3w^2+7w-7}{(w+3)(w+5)}+\dfrac{1}{(w+3)(w+5)}\\\\=\dfrac{3w^2+7w-7+1}{(w+3)(w+5)}\\\\=\dfrac{(3w-2)(w+3)}{(w+5)(w+3)}\\\\=\dfrac{3w-2}{w+5}

Ques 18)

Let the blank space be denoted by the quantity 'x'.

\dfrac{x}{12a^2+8a}+\dfrac{15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\ \\\dfrac{x+15a^2}{12a^2+8a}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a(3a+2)}=\dfrac{7a}{3a+2}\\\\=\dfrac{x+15a^2}{4a}=7a\\\\x+15a^2=28a^2\\\\x=28a^2-15a^2\\\\x=13a^2

Ques 19)

Let the missing quantity be denoted by 'x'.

\dfrac{p^2+7p+2}{p^2+5p-14}-\dfrac{x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\ \\\dfrac{p^2+7p+2-x}{p^2+5p-14}=\dfrac{p-1}{p-2}\\\\\dfrac{p^2+7p+2-x}{(p-2)(p+7)}=\dfrac{p-1}{p-2}\\\\p^2+7p+2-x=(p-1)(p+7)\\\\p^2+7p+2-x=p^2+6p-7\\\\x=p+9


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Step-by-step explanation: 3 divided by 9


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Answer:

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C. Is the correct answer
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