Please help me with number 1, thanks
1 answer:
You might be interested in
Answer:
36.50$
Step-by-step explanation:
The power of the light bulb in this problem is
P = 100 W = 0.1 kW
And the light bulb is operated for a time of
t = 10 hours
per day.
The light bulb is operated over 1 year (365 days), so the number of hours of operation is:
So the total energy consumed by the light bulb is
We know that the cost of operation is
p = 10 cents/kWh
Therefore, the total cost will be:
So, 3650 cents, or 36.50$.
Answer:
The probability that a randomly selected chocolate bar will have a. Between 200 and 220 calories will be 0.3023
Step-by-step explanation:
Given:
True mean=225
S.D=10
X1=200 and X2=220
To Find:
P(X1<x<X2)
Solution:
<em>BY using Z-table for probability and Z-score we can proceed.</em>
So
For 200 calories Z will be ,
Z=(sample mean -true mean)/S.D
=200-225/10
=-25/10
=-2.5
For 220 calories Z will be ,
Z=220-225/10
=-5/10
=-0.5
So required probability will be
=0.3023