I would say smaller than because you would be dilating the image by a number less than 1, which is making the image smaller.

First we must apply the Quotient rule that states,

This means that our derivative becomes,

Now we need to calculate
and 


From here the new equation looks like,

And that is the final result.
Hope this helps.
r3t40
Answer:
86cm
Step-by-step explanation: