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densk [106]
3 years ago
8

Please help me with number 1, thanks

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0
What don't you get about the problem ?
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True or false:<br> the following equation is in standard form. <br> (x - 4.2)^2 - 3 = 0
natita [175]

Answer:

false

Step-by-step explanation:

standard form cannot contain fractions or decimals

3 0
2 years ago
Which of these is a simplified form of the equation 8y + 4 = 6 + 2y + 1y?
larisa86 [58]
The first one would be the right one!
  
you just take all the y one side and the numbers on one side 
 so 8y+4= 6+3y

now 8y-3y= 6-4

therefore 5y = 2 
 
!!

3 0
3 years ago
Read 2 more answers
How are the solutions to the following two equations related m+5=72 <br> m+72=5
EastWind [94]
To see how they are related, let us solve the two equations.

FIRST EQUATION

m + 5 = 72

\rightarrow \: m = 72 - 5

\rightarrow \: m = 67

SECOND EQUATION

m + 72 = 5

\rightarrow \: m = 5 - 72

\rightarrow \: m = - 67

Hence the solutions to the two equations are ADDITIVE INVERSE of each other.
6 0
3 years ago
Brainliest to most helpful! Answer asap!
kap26 [50]

ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA

The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite

Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent

The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle

θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3

α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
8 0
3 years ago
YOU GET 60 POINTS!! Ronald rents a car from Cheap Rent-a-Car for $25 plus $0.05 per mile. Dixon rents a car from Great Cars for
Harlamova29_29 [7]
10 miles i think :)
8 0
3 years ago
Read 2 more answers
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