We know that
if two lines are perpendicular
then
the slopes
m1*m2=-1
step 1
find the slope AB
A (0,2)
B (-3,-3)
m=(y2-y1)/(x2-x1)-----> m=(-3-2)/(-3-0)-----> m=-5/-3----> m1=5/3
step 2
find the slope CD
C (-4,1)
D (0,-2)
m=(y2-y1)/(x2-x1)-----> m=(-2-1)/(0+4)-----> m=--3/4----> m2=-3/4
step 3
multiply mi*m2
(5/3)*(-3/4)-----> -15/12
so
15/12 is not -1
therefore
AB is not perpendicular to CD
This system has one solution y=8x+9, y=x^2+4x+13. What is the y coordinate
y=8x+9<= y=8x+9 <== 8x+9: m=8
y=x^2+4x+13<= y <==x^2+4x+13: minimum (-2,9)
y=8x+9 and y.No solution
Answer:
1/3 i believe
Step-by-step explanation:
Answer:
134+144
Step-by-step explanation:
just take the answer (278)- the number they give you
278-
134
144
25/25
1/1
2/2
7/7
18/18/
100/100