I believe the answer for 1) is
PEgrav = mass • g • height
PEgrav = m *• g • h
-- First, it can never swing to a higher elevation off the floor
than where it was when she let it go. The higher it is off the
floor, the more potential energy it has, and that's all the energy
she gave it when she lifted it to the height of her chin.
-- Second, it can't even return to THAT height, because during
its swing out and back, it's losing energy by plowing through air.
So each swing is slightly narrower, and ends slightly lower, than
the one before it.
Answer:
The y-component of the normal force is 45.74 N.
Explanation:
Given that,
Mass of the crate, m = 5 kg
Angle with hill,
We need to find the y component of the normal force. We know that the y component of the normal force is given by :
So, the y-component of the normal force is 45.74 N. Hence, this is the required solution.
The lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
To find the answer, we need to know about the Newton's equation of motion.
<h3>What's the Newton's equation of motion to find the acceleration in term of initial velocity, final velocity and distance?</h3>
- The Newton's equation of motion that connects velocity, distance and acceleration is V² - U²= 2aS
- V= final velocity, U= initial velocity, S= distance and a= acceleration
<h3>What's the acceleration, if the initial velocity, final velocity and distance are 0 m/s, 360km/h and 1.8 km respectively?</h3>
- Here, S= 1.8 km or 1800 m, V= 360km/h or 100m/s , U= 0 m/s
- So, 100²-0= 2×a×1800
=> 10000= 3600a
=> a= 10000/3600 = 2.8 m/s²
Thus, we can conclude that the lowest constant acceleration needed for takeoff from a 1.80 km runway is 2.8 m/s².
Learn more about the Newton's equation of motion here:
brainly.com/question/8898885
#SPJ4
Answer:
gas vibrates and moves freely at high speeds.
Explanation:
Hope this helps