Answer:
k. e. = 1/2 mv^2
1/2 * 1000 * (5)^2
1/2 * 1000 * 25
12500 joules
k. e. = 1/2 mv^2
1/2 * 1000 * (10)^2
1/2 * 1000 * 100
50000
change in k. e. = final - initial
50000 - 12500
= 37500 joules
hope it helps you
Answer:
The answer is "Walk three days a week, gradually adding distance and hills."
Explanation:
The FITT Principle <u>guides a person in becoming a fitter version of himself by following a particular frequency, intensity, time and type of exercise in order to achieve his goals.</u>
<u>Frequency</u>- this refers to how often a person should do an exercise. For example, 5 times a week of intense core workout.
<u>Intensity</u>- this refers to the person's vigour or strength in doing the workout. This depends whether the person is doing a high-intensity or a low-intensity exercise.
<u>Time</u>- this refers to the length of a person's exercise. This will largely depend on every individual's fitness level.
<u>Type of Exercise</u>- this refers to the exercise that a person should incorporate in his training<u> in order to avoid injuries of using the same muscles over and over again.</u>
Among the choices above, it is only the second choice (Walk three days a week, gradually adding distance and hills) that follows the FITT principle. Walking shouldn't be kept at the same pace and distance for many weeks, since it results to<em> boredom and overuse injuries. </em>This will also lead to a plateau when it comes to people who are trying to lose weight because the body has already well-adjusted to the exercise and cannot be challenged anymore.
<em>Gradually increasing the distance and hills will allow the person to be more challenged </em>and<em> </em>will also increase his desire to workout (because he is seeing results).
The coefficient of friction between the Tyre and the ground is 0.11
<u>Explanation:</u>
Given:
Radius of the track (r)=125 m.
Speed with which the car travels (v) =42 km/hr
=11.67 m/s
To Find:
Coefficient of friction between the Tyre and the ground.
Formula to be used:
We know that,Frictional force is equal to centripetal force
Frictional force=μmg
therefore 1.08 m=μmg
Cancelling "m" on both sides we get,
μ=1.08/g=1.08/9.8
=0.11
Thus the coefficient of friction between the Tyre and the ground is 0.11
Answer:
Mass is how much "stuff" is in something. Weight is a force that is measured in Newtons. A pan balance is a type of scale. A measuring cup is used to measure volume, such as cups and grams (depending if you use the metric system or not).
Explanation:
Can you make me brainliest? TYSM Als,o srry if im wrong
