Answer:
Explanation:
We shall apply Pascal's Law in fluid mechanics
According to it , pressure is transmitted in liquid from one point to another without any change .
25 cm diameter = 12.5 x 10⁻² m radius
Area = 3.14 x (12.5 x 10⁻²)²
= 490.625 x 10⁻⁴ m²
Pressure by vehicle
Force / area
13000 / 490.625 x 10⁻⁴
= 26.497 x 10⁴ Pa
5 cm diameter = 2.5 x 10⁻² radius
area = 3.14 x (2.5 x 10⁻²)²
= 19.625 x 10⁻⁴ m²
If we assume required force F on this area
Pressure = F / 19.625 x 10⁻⁴ Pa
According to Pascal Law
F / 19.625 x 10⁻⁴ = 26.497 x 10⁴
F = 19.625 x 26.497
= 520 N
Solution :
The angular acceleration,
is obtained from the equation of the
of rotational motion,
Thus,
![$\tau = F \times d$](https://tex.z-dn.net/?f=%24%5Ctau%20%3D%20F%20%5Ctimes%20d%24)
or ![$\tau = I \times \alpha$](https://tex.z-dn.net/?f=%24%5Ctau%20%3D%20I%20%5Ctimes%20%5Calpha%24)
where
is torque, F is force, d is moment arm distance, I is the moment of inertia
Thus, ![$\alpha=\frac{(F\times d)}{I}$](https://tex.z-dn.net/?f=%24%5Calpha%3D%5Cfrac%7B%28F%5Ctimes%20d%29%7D%7BI%7D%24)
Now if the force and the moment arm distance are constant, then the
That is when, F = d = constant, then
.
Thus, moment of inertia, I is proportional to mass of the bar.
The mass is less for the bar in case (1) in comparison with that with the bar in case (2) due to the holes that is made in the bar.
Therefore, the bar in case (1), has less moment of inertia and a greater angular acceleration.
Answer:
A natural magnet is a magnet that occurs naturally in nature. Artificial magnets are magnets made by people. ... An example of a natural magnet is the lodestone, also called magnetite. Other examples are pyrrhotite, ferrite, and columbite.
Answer:
![-2.00876\times 10^{-18}\ J](https://tex.z-dn.net/?f=-2.00876%5Ctimes%2010%5E%7B-18%7D%5C%20J)
Explanation:
v = Speed of electron =
(generally the order of magnitude is 6)
m = Mass of electron = ![9.11\times 10^{-31}\ kg](https://tex.z-dn.net/?f=9.11%5Ctimes%2010%5E%7B-31%7D%5C%20kg)
Work done would be done by
![W=K_i-K_f\\\Rightarrow W=0-\dfrac{1}{2}mv^2\\\Rightarrow W=0-\dfrac{1}{2}\times 9.11\times 10^{-31}\times (2.1\times 10^6)^2\\\Rightarrow W=-2.00876\times 10^{-18}\ J](https://tex.z-dn.net/?f=W%3DK_i-K_f%5C%5C%5CRightarrow%20W%3D0-%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5CRightarrow%20W%3D0-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.11%5Ctimes%2010%5E%7B-31%7D%5Ctimes%20%282.1%5Ctimes%2010%5E6%29%5E2%5C%5C%5CRightarrow%20W%3D-2.00876%5Ctimes%2010%5E%7B-18%7D%5C%20J)
The work required to stop the electron is ![-2.00876\times 10^{-18}\ J](https://tex.z-dn.net/?f=-2.00876%5Ctimes%2010%5E%7B-18%7D%5C%20J)