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Papessa [141]
3 years ago
8

A person slides a box down a ramp. The box starts from rest 2m above the lowest point. The ramp is frictionless. Once the box re

aches the bottom there is friction. For every 1m the box travels on the flat part increases by 100 J. Where does the box stop? The box has mass of 5 kg.
Physics
1 answer:
Eva8 [605]3 years ago
6 0

Answer:

.98m

Explanation:

Vf=Vi+2at

(V F)^2+2 ( change in distance )

X f= i ( change in V & T )

EK=1/2Mv^2,EG=mgh

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When liquid silver nitrate and liquid sodium chloride are combined, solid silver chloride forms along with a new liquid, sodium
Karolina [17]

Answer:

Silver Chloride

Explanation:

A <em>precipitate</em> in chemistry is a substance that becomes solid during a chemical reaction.

Have a great day!

4 0
2 years ago
A circular steel wire 3.00 mm long must stretch no more than 0.25 cmcm when a tensile force of 780 NN is applied to each end of
fgiga [73]

Minimum diameter is required for the wire is 1.2X10⁻³m.

Tensile force, which consists of tensile stress and tensile strain, is the stretching force exerted on the material. This indicates that the forces are attempting to stretch the material that is subject to the force since it is under tension.

Given;

Tensile force (ft) = 780 N

length (l) = 3.00 mm

change in length (Δl) = 0.25 cm

determine the strain ε = Δl/l

determine the stress σ = Eε = E(Δl/l)

determine the cross-sectional area A = f/σ = ft/EΔl

determine the diameter d = 2\sqrt{} \frac{A}{\pi } = 2\sqrt{} \frac{ft}{EXΔlX\pi }

take Young's modulus for steel E=200 GPa, Substitute the values,

d = \sqrt[2]{\frac{x780X2}{y200X10^{9} X 0.0025\pi } } = 1.2X10⁻³

minimum diameter is required for the wire is 1.2X10⁻³m.

Learn more about the Tensile force with the help of the given link:

brainly.com/question/4443489

#SPJ4

I understand that the question you are looking for is "A circular steel wire 3.00 cm long must stretch no more than 0.25 cm when a tensile force of 780 N is applied to each end of the wire. What minimum diameter is required for the wire?"

4 0
1 year ago
During maneuvers preceding the Battle of Jutland, the British battle cruiser Lion moved as follows (in nautical miles): 1.2 mile
lana66690 [7]

Answer:

total distance is 11.3 miles

Explanation:

Given data:

distance to north = 1.2 miles

distance to south at 38 degree east of south = 6.1 miles  

distance to east of north at angle 89 degree = 4 miles  

distance to east of north at angle 31 degree =  6.5 miles

considering each displacement as vector so we have

\begin{pmatrix}0.0\\  1.2\end {pmatrix}   + \begin {pmatrix}3.8\\  -4.8\end{pmatrix} +\begin{pmatrix}4.0\\  0.1\end {pmatrix}+\begin{pmatrix}3.3\\  5.6\end{pmatrix} = \begin{pmatrix}11.1\\  2.1\end{pmatrix}

total distance is \sqrt{11.1^2 + 2.1^2} \approx  11.3

5 0
3 years ago
What are two force componentes of projectile motion
Alika [10]

Answer:

Horizontal Motion, and Vertical Motion.

Explanation:

5 0
3 years ago
Is fe a reactant or product
DedPeter [7]
Reactant is the answer
4 0
3 years ago
Read 2 more answers
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