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2 years ago

Write an explicit formula for an, the nth term of the sequence 19,24,29

Mathematics

1 answer:

o-na [289]2 years ago

3 0

Answer:

explicit formula for an, the nth term of the sequence 19,24,29

$a_1=19 ; \ a_n=a_{n-1}+5$

Step-by-step explanation:

We need to Write an explicit formula for an, the nth term of the sequence 19,24,29

In the sequence the First term a₁= 19

Common Difference d= 5

The Formula used for explicit formula is: $a_1=First \ term ; \ a_n=a_{n-1}+d$

Where d is common difference and n is nth term of sequence.

So, explicit formula for an, the nth term of the sequence 19,24,29

$a_1=19 ; \ a_n=a_{n-1}+5$

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2 years ago

How do you find an exact value for sin of 40 degrees without using a calculator

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2 years ago

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drek231 [11]

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2 years ago

Three of four numbers have a sum of 22. If the average of the four numbers is 8, what is the fourth number ?

KatRina [158]

X+y+z=22

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2 years ago

Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then

tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

$\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x$

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

$\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x$

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

$\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x$

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

$\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x$

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

$\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x$

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

$\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}$

Compute the number of candies in the sixth jar as follows:

$\text{Number of candies in the 6th jar}=\frac{63}{32}x\\$

$=\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42$

Thus, the number of candies in the sixth jar is 42.

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2 years ago