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mel-nik [20]
3 years ago
11

Write an explicit formula for an, the nth term of the sequence 19,24,29

Mathematics
1 answer:
o-na [289]3 years ago
3 0

Answer:

explicit formula for an, the nth term of the sequence 19,24,29

a_1=19 ; \ a_n=a_{n-1}+5

Step-by-step explanation:

We need to Write an explicit formula for an, the nth term of the sequence 19,24,29

In the sequence the First term a₁= 19

Common Difference d= 5

The Formula used for explicit formula is: a_1=First \ term ; \ a_n=a_{n-1}+d

Where d is common difference and n is nth term of sequence.

So, explicit formula for an, the nth term of the sequence 19,24,29

a_1=19 ; \ a_n=a_{n-1}+5

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What is the average rate of change from x= -1 to x = 1 ?
Masteriza [31]

Answer:

  -2

Step-by-step explanation:

The average rate of change on an interval is ...

  average rate of change = (amount of change)/(width of interval)

  = (-3 -1)/(1 -(-1)) = -4/2 = -2

The average rate of change between (-1, 1) and (1, -3) is -2.

3 0
3 years ago
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What is the mean in 74,75,80,76,75,81,78?
Alina [70]

Answer:

77

Step-by-step explanation:

Add the numbers together, then divide them to how much numbers are there.

74 + 75 + 80 + 76 + 75 + 81 + 78 = 539

Since there are 7 numbers, you divide 539 by 7.

539/7 = 77

6 0
3 years ago
Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into
Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = (\frac{60\pi }{\pi+4}) in

b)the length of the wire for the square = (\frac{240}{\pi+4}) in

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

         b=\frac{y}{4}

Area of the square which is L² can now be said to be;

A_S=(\frac{y}{4})^2 = \frac{y^2}{16}

On the otherhand; let the radius (r) of the  circle be;

2πr = 60-y

r = \frac{60-y}{2\pi }

Area of the circle which is πr² can now be;

A_C= \pi (\frac{60-y}{2\pi } )^2

     =( \frac{60-y}{4\pi } )^2

Total Area (A);

A = A_S+A_C

   = \frac{y^2}{16} +(\frac{60-y}{4\pi } )^2

For the smallest possible area; \frac{dA}{dy}=0

∴ \frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0

If we divide through with (2) and each entity move to the opposite side; we have:

\frac{y}{18}=\frac{(60-y)}{2\pi}

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

y= \frac{240}{\pi+4}

∴ since y= \frac{240}{\pi+4}, we can determine for the length of the circle ;

60-y can now be;

= 60-\frac{240}{\pi+4}

= \frac{(\pi+4)*60-240}{\pi+40}

= \frac{60\pi+240-240}{\pi+4}

= (\frac{60\pi}{\pi+4})in

also, the length of wire for the square  (y) ; y= (\frac{240}{\pi+4})in

The smallest possible area (A) = \frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0
3 years ago
The candle company is having its semiannual sale. All items are 40 percent off. If the original price of a candle basket is $120
Stells [14]

Answer:

It's C

Step-by-step explanation:

120 x 0.4 = 48

120 - 48 = 72

6 0
3 years ago
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ratelena [41]
We'll check if they're orthogonal:
u*v=0
(6,-2)*(8,24)=0
6*8+(-2)*24=0
48-48=0
0=0
they are orthogonal vectors
4 0
3 years ago
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