Easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
h(I(s))=-4s^2-12s-13
Answer:
the second one (Diego)
Step-by-step explanation:
7a-3a
5b+4b
#3 is not a function because there are two answers for one out put
#4 is a function because it is a straight line
In order to solve this, you have to look at the order for each of the variable terms. In this case t is your variablr
<span>4<span>t0</span>=4</span>
exponent is 0.
<span>−<span>t1</span>=−t</span>
exponent is 1.
<span>t2</span>
exponent is 2.
So you order them by exponents from least to greatest (ascending).
<span><span>4−t+<span>t2</span></span></span>
