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Harrizon [31]
2 years ago
15

State the conditions required for a random variable x to follow a poisson process.

Mathematics
1 answer:
inessss [21]2 years ago
5 0

The conditions required for a random variable X to follow a Poisson process. The probability of success is the sme for aany two intervals of equal length. The probability of two or more successes in any sufficiently small subinterval is 0.

<h3>Is the time required to upload a file to the Internet discrete or continuous?</h3>
  • Is the length of time it takes to download a file from the Internet a random variable, a continuous random variable, or not at all? A continuous random variable, that is.

<h3>Is the a discrete random variable a continuous random variable or not a random variable?</h3>
  • A variable whose value is determined by counting is referred to as a discrete variable.
  • A continuous variable is one whose value may be determined through measurement.
  • A random variable is a variable whose value is the resultant number of an unpredictable event.
  • There are a countable number of potential values for the discrete random variable X.

<h3>How do you determine whether the random variable is discrete or continuous?</h3>
  • A discrete variable is one that is random.
  • if the number of possible values is either countable or finite. Continuous refers to a variable that is random.
  • if the range of possible values includes all conceivable numbers.

Learn more about continuous function here:

brainly.com/question/18102431

#SPJ4

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Will give brainliest answer to whoever answers correctly and explains how they got their answer. I've been working on this for h
Oksanka [162]
A1/27 = A2/39 =>

A2 = A1*39/27

A2 = 711×39/27

A2 = 1027 m^2
5 0
3 years ago
Decide whether the relation is a function:<br> {(-3, 7), (1, -8), (6, -6), (7-8), (12, 2)}
lakkis [162]

Answer:

It is a function

Step-by-step explanation:

A function is of the form:

\left[\begin{array}{c}x_1&x_2&x_3\\-&-&-\\x_n\end{array}\right]            \left[\begin{array}{c}y_1&y_2&y_3\\-&-&-\\y_n\end{array}\right]

Where each of the x values must be distinct.

The x values are referred to as domain while the y values are called range.

Having said that, the given data can be represented as follows:

\left[\begin{array}{c}-3&1&6\\7&12\end{array}\right] ----------- \left[\begin{array}{c}7&-8&-6\\-8&2\end{array}\right]

<em>From the representation above, none of the x values are repeated.</em>

<em>Hence, it is a function</em>

6 0
3 years ago
2. Bob the plumber charges $15 per hour plus a service fee of $40 for coming out to your house. Which function models this situa
Andrew [12]

Answer:

B

Step-by-step explantion:

X is the amount of hours. Since they are charging 15 per hour you would have to multiply how many hours (x) by 15. Then add 40. And y equals the total amount pls mark brainliest

6 0
3 years ago
intext:"A shipment of 50 inexpensive digital​ watches, including 6 that are​ defective, is sent to a department store. The recei
andrezito [222]

Answer:

0.7125

Step-by-step explanation:

The binomial distribution with parameters n and p is the discrete probability distribution of the number of successes (with probability p) in a sequence of n independent events.

The probability of getting exactly x successes in n independent Bernoulli trials =  n_{C_{x}}(p)^x(1-p)^{n-x}

Total number of watches in the shipment = 50

Number of defective watches = 6

Number of selected watches = 10

Let X denotes the number of defective digital watches such that the random variable X follows a binomial distribution with parameters n and p.

So,

Probability of defective watches = \frac{X}{n}=\frac{6}{50}=0.12

Take n = 10 and p = 0.12

Probability that the shipment will be rejected = P(X\geq 1)=1-P(X=0)

=1-n_{C_{x}}(p)^x(1-p)^{n-x}\\=1-10_{C_{0}}(0.12)^0(1-0.12)^{10-0}

Use n_{C_{x}}=\frac{n!}{x!(n-x)!}

So,

Probability that the shipment will be rejected = =1-\left ( \frac{10!}{0!(10-0)!} \right )(0.88)^{10}

=1-(0.88)^{10}\\=1-0.2785\\=0.7125

6 0
3 years ago
23+k+h
IRISSAK [1]
"Sum" means the result of adding.
8 0
3 years ago
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