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Harrizon [31]
2 years ago
15

State the conditions required for a random variable x to follow a poisson process.

Mathematics
1 answer:
inessss [21]2 years ago
5 0

The conditions required for a random variable X to follow a Poisson process. The probability of success is the sme for aany two intervals of equal length. The probability of two or more successes in any sufficiently small subinterval is 0.

<h3>Is the time required to upload a file to the Internet discrete or continuous?</h3>
  • Is the length of time it takes to download a file from the Internet a random variable, a continuous random variable, or not at all? A continuous random variable, that is.

<h3>Is the a discrete random variable a continuous random variable or not a random variable?</h3>
  • A variable whose value is determined by counting is referred to as a discrete variable.
  • A continuous variable is one whose value may be determined through measurement.
  • A random variable is a variable whose value is the resultant number of an unpredictable event.
  • There are a countable number of potential values for the discrete random variable X.

<h3>How do you determine whether the random variable is discrete or continuous?</h3>
  • A discrete variable is one that is random.
  • if the number of possible values is either countable or finite. Continuous refers to a variable that is random.
  • if the range of possible values includes all conceivable numbers.

Learn more about continuous function here:

brainly.com/question/18102431

#SPJ4

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25% of all who enters a race do not complete. 30 haveentered.
nikklg [1K]

Answer:

The probability that exactly 5 are unable to complete the  race is 0.1047

Step-by-step explanation:

We are given that 25% of all who enters a race do not complete.

30 have entered.

what is the probability that exactly 5 are unable to complete the  race?

So, We will use binomial

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p is the probability of success i.e. 25% = 0.25

q is the probability of failure =  1- p  = 1-0.25 = 0.75

We are supposed to find the probability that exactly 5 are unable to complete the  race

n = 30

r = 5

P(X=5) =^{30}C_5 (0.25)^5 (0.75)^{30-5}

P(X=5) =\frac{30!}{5!(30-5)!} \times(0.25)^5 (0.75)^{30-5}

P(X=5) =0.1047

Hence the probability that exactly 5 are unable to complete the  race is 0.1047

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