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3 years ago

10

The sponsor of a 5k run/walk for charity wishes to create a stamp of its billboard to commemorate the event.If the sponsor uses

a scale where 1 inch represents 4 feet, and the billboard is a rectangle with a width of 14 feet and a length of 48 feet, what will be the shape and size of the stamp?
Please answer....

2 answers:

pickupchik [31]3 years ago

8 0

1 inch = 4 ft

so 14 ft = 14/4 = 3.5 inches (width)
48 ft = 48/4 = 12 inches (length)

so ur gonna end up with a rectangle with a width of 3.5 inches and a length of 12 inches

jeyben [28]3 years ago

3 0

ANSWER:

GIVEN:

<u>billboard</u>

$1inch =4feet\\width=14feet\\length=48feet$

To find the shape and size of <u>stamp:</u>

$14/4=7/2=3.5 inch(width)\\48/4=12inch (length)$

so the stamp is a rectangle with a width 3.5 inch and length of 12 inch.

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Likurg_2 [28]

Answer: Hello! I believe your answer would be 162.

Step-by-step explanation: So the formula for Area on a rectangle is WxL. So length will be 9. But if you notice on the scale rectangle the width is the length times two. So the length on the real garden is 18.

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3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

please can someone help me with this question? i will mark brainliest and i would also really appreciate it! :)

Sloan [31]

Answer:

y ≤ 3x- 1

Step-by-step explanation:

The line is solid, so your answer must have a ≤ or ≥ symbol. And the area below the line is shaded so you would also know you answer must have a ≤ or < symbol.

8 0

2 years ago

Read 2 more answers

Omg someone pleaseeee help me!!! 30 points!!!

Crank

add the volume of a cone, V=1/3 pi times radius squared times h. The volume of the cone is V=355. Then you add the volume of the cone to the volume of the cylinder. the formula for the volume of a cylinder is V= pi times radius squared times h. So the volume of the cylinder will be V=923. if you add those two together the overall volume is 1,278.

8 0

3 years ago

Simplify the expression -3 devided by -2/5. A. -7 1/2 B. -1 1/5 C. 1 1/5 D. 7 1/2

Llana [10]

Answer:

D. 7 1/2

Step-by-step explanation:

-3 divided by -2/5

-(-3(-5/2)

-(-3 x 5/2)

-15/2

7 1/2

Hope it helps

7 0

3 years ago