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GaryK [48]
3 years ago
10

The sponsor of a 5k run/walk for charity wishes to create a stamp of its billboard to commemorate the event.If the sponsor uses

a scale where 1 inch represents 4 feet, and the billboard is a rectangle with a width of 14 feet and a length of 48 feet, what will be the shape and size of the stamp?
Please answer....
Mathematics
2 answers:
pickupchik [31]3 years ago
8 0
1 inch = 4 ft

so 14 ft = 14/4 = 3.5 inches (width)
48 ft = 48/4 = 12 inches (length)

so ur gonna end up with a rectangle with a width of 3.5 inches and a length of 12 inches
jeyben [28]3 years ago
3 0

ANSWER:

GIVEN:

<u>billboard</u>

1inch =4feet\\width=14feet\\length=48feet

To find the shape and size of <u>stamp:</u>

14/4=7/2=3.5 inch(width)\\48/4=12inch (length)

so the stamp is a rectangle with a width 3.5 inch and length of 12 inch.

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boyakko [2]

Move all terms to one side

4w^2 + 49 + 28w = 0

Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7

(2w)^2 + 2(2w)(7) + 7^2 = 0

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(2w + 7)^2 = 0

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2w = -7

Divide both sides by 2

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Step-by-step explanation:

(a-b)^2=a^2-2ab+b^2\\\\2x^2-4x-9=0\qquad|\text{add 9 to both sides}\\\\2x^2-4x-9+9=0+9\\\\2x^2-4x=9\qquad|\text{divide both sides by 2}\\\\\dfrac{2x^2}{2}-\dfrac{4x}{2}=\dfrac{9}{2}\\\\x^2-2x=4.5\\\\x^2-2\cdot x\cdot1=4.5\qquad|\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2\cdot x\cdot1+1^2=4.5+1^2\\\\(x-1)^2=5.5\iff x-1=\pm\sqrt{5.5}\qquad|\text{add 1 to both sides}\\\\x=1-\sqrt{5.5}\ \vee\ x=1+\sqrt{5.5}

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See the pic above!

Hope it helps!

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Peter has one of each of the following coins in his pocket: a penny, a nickel, a dime, a quarter, and a half-dollar. Four of the
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Step-by-step explanation:

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Answer:

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