Answer:
x+4=20 is a solution to 5(x+4)=100.
Step-by-step explanation:
Following PEMDAS, divide 5 from both sides of the equation 5(x+4)=100, and you have x+4=20 remaining.
This means that both equations have the same solution.
Answer:2/11
Step-by-step explanation:
A fraction is in simplest form when the top and bottom cannot be any smaller
Firstly start by getting the common factors between 1 and 4 in 1/4 and 11 and 8 in 11/8. The common factor is 1 in 1/4 and 1 in 11/8. 1÷1/4÷1= 1/4. 11÷1/8÷1 = 11/8.
1/4÷ 11/8 =2/11.
Answer: 26
Step-by-step explanation: The order of operations says to divided 8 and 2 first, which gives you 4. 18+4=22. Plus 4 again is 26
The correct option is (B) yes because all the elements of set R are in set A.
<h3>
What is an element?</h3>
- In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.
Given sets:
- U = {x | x is a real number}
- A = {x | x is an odd integer}
- R = {x | x = 3, 7, 11, 27}
So,
- A = 1, 3, 5, 7, 9, 11... are the elements of set A.
- R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
- Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.
Therefore, the correct option is (B) yes because all the elements of set R are in set A.
Know more about sets here:
brainly.com/question/2166579
#SPJ4
The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?
(A) yes, because all the elements of set A are in set R
(B) yes, because all the elements of set R are in set A
(C) no because each element in set A is not represented in set R
(D) no, because each element in set R is not represented in set A
You have to take the amount of money payed, which in this case is 45.50, and divide it with 7.
