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Anika [276]
3 years ago
15

Lightning and thunder take place in the sky at the same time and at the same distance from us. Lightning is seen earlier and thu

nder is heard later, Explain why?
Physics
1 answer:
Tasya [4]3 years ago
3 0

Answer:

Lightning is seen earlier than the thunder because speed of light is more than the speed of sound. Therefore, even though both occurs as same time and place in the sky, lightning is seen earlier.

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On the sonometer shown below, a horizontal cord of length 5 m has a mass of 1.45 g. When the cord was plucked the wave produced
Korolek [52]

Answer:

(a) T = 0.015 N

(b) M = 1.53 x 10⁻³ kg = 1.53 g

Explanation:

(a) T = 0.015 N

First, we will find the speed of waves:

v =f\lambda

where,

v = speed of wave = ?

f = frequency = 120 Hz

λ = wavelength = 6 cm = 0.06 m

Therefore,

v = (120 Hz)(0.06 m)

v = 7.2 m/s

Now, we will find the linear mass density of the coil:

\mu = \frac{m}{l}

where,

μ = linear mass density = ?

m = mass = 1.45 g = 1.45 x 10⁻³ kg

l = length = 5 m

Thereforre,

\mu = \frac{1.45\ x\ 10^{-3}\ kg}{5\ m}\\\\\mu = 2.9\ x\ 10^{-4}\ kg/m

Now, for the tension we use the formula:

v = \sqrt{\frac{T}{\mu}}\\\\7.2\ m/s = \sqrt{\frac{T}{2.9\ x\ 10^{-4}\ kg/m}}\\\\(51.84\ m^2/s^2)(2.9\ x\ 10^{-4}\ kg/m) = T

<u>T = 0.015 N</u>

<u></u>

(b)

The mass to be hung is:

T = Mg\\\\M = \frac{T}{g}\\\\M = \frac{0.015\ N}{9.8\ m/s^2}\\\\

<u>M = 1.53 x 10⁻³ kg = 1.53 g</u>

4 0
3 years ago
How would the future of the universe differ from the past?
zhuklara [117]
Everything would be more advanced and logical while the past people really just tried to survive.
3 0
3 years ago
A 12.0 V car battery is being used to power the headlights of a car. Each of the two headlights has a power rating of 37.7 Watts
marshall27 [118]

Answer:

3.921*10^19 electrons

Explanation:

To find the number of electron that trough the car battery you first calculate the current by using the following formula, which relates the power with the voltage:

P=IV          (1)

P: power of both headlights = 2(37.7W) = 75.4 W

I: current = ?

V: voltage of the battery = 12.0 V

You solve the equation (1) for I:

I=\frac{P}{V}=\frac{75.4W}{12.0V}=6.283A=6.238\frac{C}{s}

Next, you use the equivalence 1C = 6.241*10^18 electrons:

6.238\frac{C}{s}*\frac{6.241*10^{18}\ electrons}{1C}=3.921*10^{19}\ electrons/s

The number of electrons that cross the battery per second is 3.921*10^19 electrons

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3 years ago
The gauge pressure for the air in a balloon equals 1.01 x 10^5 Pa. If atmospheric pressure is equal to 1.01 x 10^5 Pa, what is t
Kobotan [32]
Absolute Pressure = Atmospheric Pressure + Gage Pressure

Absolute Pressure = 1.01 x 10^5 Pa + 1.01 x 10^5 Pa = D. <span>2.02 x 10^5 Pa</span>
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