(a) The angular acceleration of the wheel is given by
![\alpha = \frac{\omega_f - \omega_i }{t}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%20%5Cfrac%7B%5Comega_f%20-%20%5Comega_i%20%7D%7Bt%7D%20)
where
![\omega_i](https://tex.z-dn.net/?f=%5Comega_i)
and
![\omega_f](https://tex.z-dn.net/?f=%5Comega_f)
are the initial and final angular speed of the wheel, and t the time.
In our problem, the initial angular speed is zero (the wheel starts from rest), so the angular acceleration is
![\alpha = \frac{(11.2 rad/s) - 0}{3.07 s} =3.65 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%20%5Cfrac%7B%2811.2%20rad%2Fs%29%20-%200%7D%7B3.07%20s%7D%20%3D3.65%20rad%2Fs%5E2)
(b) The wheel is moving by uniformly rotational accelerated motion, so the angle it covered after a time t is given by
![\theta (t) = \omega_i t + \frac{1}{2} \alpha t^2](https://tex.z-dn.net/?f=%5Ctheta%20%28t%29%20%3D%20%5Comega_i%20t%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%5Calpha%20t%5E2%20)
where
![\omega_i = 0](https://tex.z-dn.net/?f=%5Comega_i%20%3D%200)
is the initial angular speed. So, the angle covered after a time t=3.07 s is
For the electric field is measured for points at distances r,Electric field is mathematically given as
E=19.9*10^{-5}c/m^3
<h3>What is the
Electric field?</h3>
Generally, the equation for the electric field uniform charged is mathematically given as
![E=\frac{lr}{3e0}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Blr%7D%7B3e0%7D)
Therefore
E=lr/3E0=3Ee0/r
Therefore
E=3*6*10^4*8.85*10^{-12}
E=19.9*10^{-5}c/m^3
In conclusion, E=19.9*10^{-5}c/m^3
E=19.9*10^{-5}c/m^3
Read more about Electric field
brainly.com/question/9383604
CQ
Complete question attached below
Answer:
4km/hr
Explanation:
There are 60 minute in an hour. If you divided 60 by 30 minutes you’d get 2. 2x 2km is 4km and 30x 2 is 60/an hour
The redshift of light from galaxies and the uniform distribution of cosmic background radiation