Answer:
v = 17.71 m / s
Explanation:
We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity
v² = v₀² - 2 g (y -y₀)
v² = 0 - 2g (y -y₀)
when it hits the stone the height is zero and part of the height of the seagull I
v² = 2g y₀
v = Ra (2g i)
let's calculate
v =√ (2 9.8 16)
v = 17.71 m / s
Answer:
The meaurement of the amount of friction a surface will generate is called the coefficient of friction.
Answer:
kinetic energy = 1 / 2 mv²
kinetic energy = 1 / 2 × 20 × 10 ²
kinetic energy = 1000 joules
.........
1. To solve this problem you can use the formula:
Force = mass × acceleration
16 = 5 × a
16/5 = a
3.2 m/sec^2 = acceleration
2. To solve this formula use the same formula that was given above:
F = ma
F= 1239 kg × 4m/sec
F = 4956 N
3. To solve this problem use the formula:
Weight = mass × gravity
W = 35 × 9.8
W = 343 N
4. To solve this problem use the formula:
Momentum = mass × velocity
M = 95 kg × 8 m/s
M = 760 kg × m/sec
hope this helps :)
Answer:
Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A
Explanation:
Let the depth of each section is h.
That means the real depth for each section is h.
Apparent depth is liquid A is 7 cm.
Apparent depth in liquid B is 6 cm.
Apparent depth in liquid C is 5 cm.
by the formula of the refractive index
n = real depth / apparent depth
where, n is the refractive index of the liquid.
For liquid A:
.... (1)
For liquid B:
..... (2)
For liquid C:
..... (3)
By comparing all the three equations
nc > nB > nA
Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A