In practice, if a voltmeter was connected across any combination of the terminals, the potential difference would be less than w
1 answer:
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Answer:
a) Acceleration, a = -u/9, where u is the initial velocity
b) Acceleration = 0.741 m/s², Initial velocity = 6.67 m/s
Explanation:
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
a) We have v = 0 m/s, t = 9 s
So, 0 = u + a x 9
Acceleration, a = -u/9, where u is the initial velocity
b) We have equation of motion , , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
s = 30 m , u = -9a, t =9 s
So,
u = -9a = 6.67 m/s
So acceleration = 0.741 m/s², Initial velocity = 6.67 m/s