Short answer: v = 10 m/s
Comment
This is just an application of KE = 1/2 m v^2
Givens
KE = 100 Joules
m = 2 kg
v = ???
Formula
KE = 1/2 m v^2
Substitution and Solve
100 = 1/2 * 2 * v^2
100 = v^2 Take the square root of both sides.
sqrt(100) = sqrt(v^2)
v = 10 m/s
Comment
There is no KE unless v > 0.
You may have PE when v = 0, but not KE.
Answer:
C)You should use the thin cooking twine.
Explanation:
A)You can choose either because they are the same length and will produce the same wave speed.
B)You should use the heavy rope.
C)You should use the thin cooking twine.
The speed of wave in a string is given by the following formula:
|
| = 
Where |
| = speed of wave,
= tension in the string, and μ = mass per length of the string.
<em>Even though the two strings have the same length, the μ (mass/length) for the heavy rope will be more than the that of a thin rope. Consequently, the </em>
<em>:μ for the thin rope will be higher than that of the heavy rope and as such, gives a bigger |</em>
<em>|. </em>
Therefore, the thin rope should be used in order to get a faster wave speed in the telephone.
The correct option is C.
Answer:
a) 
b) 
c) 
d) 
Explanation:
Average translation kinetic energy (
) is given as
....................(1)
where,
k = Boltzmann's constant ; 1.38 × 10⁻²³ J/K
T = Temperature in kelvin
a) at T = 27.8° C
or
T = 27.8 + 273 = 300.8 K
substituting the value of temperature in the equation (1)
we have

b) at T = 143° C
or
T = 143 + 273 = 416 K
substituting the value of temperature in the equation (1)
we have

c ) The translational kinetic energy per mole of an ideal gas is given as:

here
= Avagadro's number; ( 6.02×10²³ )
now at T = 27.8° C


d) now at T = 143° C


Answer:
α=0.625rad/s^2
v=340m/s
w=10rad/s
θ=320rad
Explanation:
Constant angular acceleration = ∆w/∆t
angular acceleration = 20/32
α=0.625rad/s^2
Linear velocity v=wr
v = 20×17= 340m/s
Average angular velocity
w0+w1/2
w= 0+20/2
w= 20/2
w=10rad/s
What angle did it rotate with
θ=wt
θ= 10×32
=320rad