It would be 4.0
please can i have a brailiest
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
I used to shovel snow for $5 an hour.
If ' t ' was the number of hours I spent shoveling somebody's driveway,
then ' 5t ' was the number of dollars he owed me for the job.
' t ' didn't even have to be a whole number. It worked fine with any number.
Answer:
b=15
Step-by-step explanation:
7(b+1)=2*56 (we cross multiply)
7b+7=112
7b=105
b=15
