The function g(x) is g(x)= (3x)^2
<h3>
How to solve for g(x)?</h3>
The complete question is in the image
From the graph in the image, we have:
f(x) = x^2
The function f(x) is stretched by a factor of 3 to form g(x).
This means that:
g(x) = f(3x)
So, we have:
g(x)= (3x)^2
Hence, the function g(x) is g(x)= (3x)^2
Read more about function transformation at:
brainly.com/question/10222182
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Answer:
Step-by-step explanation:
Congruent is the same size and same shape. When a ray bisects an angle, the two newly created angles will be congruent, since the ray went right in the middle of the first angle (so in this case, ABC and DBC will be congruent)
Answer:
The inverse for log₂(x) + 2 is - log₂x + 2.
Step-by-step explanation:
Given that
f(x) = log₂(x) + 2
Now to find the inverse of any function we put we replace x by 1/x.
f(x) = log₂(x) + 2
f(1/x) =g(x)= log₂(1/x) + 2
As we know that
log₂(a/b) = log₂a - log₂b
g(x) = log₂1 - log₂x + 2
We know that log₂1 = 0
g(x) = 0 - log₂x + 2
g(x) = - log₂x + 2
So the inverse for log₂(x) + 2 is - log₂x + 2.
Answer:
=5/21L+ -5/84
Step-by-step explanation:
=-(5/7) (-(1L/3-3/4)+1/3/4)
=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)
=5/21L= -15/28+ -5/84
=5/21L=+ -25/42
