Hello there.
<span>Which line is a graph of the equation 2x + 5y = 10?
Coordinate plane with the following lines graphed: Line A contains a slope of five-halves and y-intercept of 2; Line B contains a slope of negative five-halves and y-intercept of 2; Line C contains a slope of five-halves and y-intercept of negative 2; and Line D contains a slope of negative five-halves and y-intercept of negative 2.
</span><span>line b</span>
180*$7.50= 1350, that is correct answer I think
These require you solve for y. Do that by subtracting the x-term, then dividing by the y-coefficient.
5. 3y = 7x -9
y = (7/3)x -3
6. 6y = -2x -3
y = (-2/6)x -3/6
y = (-1/3)x -1/2
7. 8y = 2x + 12
y = (1/4)x +3/2
Hi there!
Th' Eqn. is :-
4 (x - 3) = 2 (3x + 1)
=> 4x - 12 = 2 (3x + 1)
=> 4x - 12 = 6x + 2
Combine th' like terms :-
=> 4x - 6x = 2 + 12
=> - 2x = 14
=> x =
=> x = - 7
Hence, The required answer is : x = - 7
~ Hope it helps!
Answer: 40
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Explanation:
The angle we want is QPR (bottom left), which is one of the base angles. The other base angle is QRP (bottom right). These two angles are equal because PQR is an isosceles triangle (PQ = RQ)
So if we can find angle QRP, then we have found angle QPR
Note how angle QRP and the 140 degree angle combine to form a straight 180 degree angle. Therefore these two angles add to 180 degrees
(angle QRP) + (140) = 180
(angle QRP) + 140 - 140 = 180-140 ... subtract 140 from both sides
angle QRP = 40
Since,
angle QPR = angle QRP
this means
angle QPR = 40
and
b = 40
