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Vlada [557]
4 years ago
9

Choose what the expressions below best represent within the context of the word problem.

Mathematics
2 answers:
grin007 [14]4 years ago
8 0

Answer:

The given expression "The sum of two consecutive odd integers equals 12." is written as 2x + 1 + 2x + 3 = 12  and numbers are 5 and 7

Step-by-step explanation:

 Given expression : The sum of two consecutive odd integers equals 12.

We have to write the given expression mathematically and solve.

Consider the given expression "The sum of two consecutive odd integers equals 12."

Consecutive odd integers are the odd integers having difference of two in between like 3, 5, 7 etc,

we know odd numbers are of the form of (2m+1)

Thus, let two consecutive odd integers be 2x+1 and 2x+3

Then given sum of  two consecutive odd integers  is 12

mathematically written as,

2x + 1 + 2x + 3 = 12

4x+ 4 = 12

x + 1 = 3

x = 2

Thus, consecutive odd integers are 2(2)+1 = 5

and 2(2) + 3 = 7

Thus, the given expression "The sum of two consecutive odd integers equals 12." is written as 2x + 1 + 2x + 3 = 12  and numbers are 5 and 7

Fed [463]4 years ago
5 0
X+Y= 12. Consecutive means in order, so in this case two odd numbers back to back. 5 and 7 are the two consecutive odd integers equal 12.
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Using traditional methods, it takes 9696 hours to receive a basic flying license. A new license training method using Computer A
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The value of the test statistic is -1.53            

Step-by-step explanation:

Step-by-step explanation:

We are given the following in the question:

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z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

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3 0
3 years ago
a city council has 12 members. Five are democratss and seven are republicans. How many ways can a four member comitte be selecte
Nostrana [21]

Answer: 495ways

Step-by-step explanation:

Selecting some b people from a group of people are based on combination principle.

If we are selecting "r'' people from a total number of 'n' people, we will have;

nCr = n!/(n-r)!r!

Since 4 people are to be selected from a committee of 5democrats and 6republicans,

Note that the question is not specific as to how many from Republicans and Democrats to select that will make the 4people,

Therefore, the selection can be done in this manner

- 0people from democrats and 4peoples from Republicans

5C0 × 7C4 = 5!/5!0! × 7!/3!4!

= 1×35= 35ways

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5C1 × 7C3 = 5×35 = 175ways

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5C2 × 7C2 = 10 × 21 = 210ways

- 3peoples from democrats and 1people from Republicans

5C3 × 7C1 = 10 × 7 = 70ways

- 4peoples from democrats and 0people from Republicans

5C4 × 7C0 = 5 × 1 = 5ways

Adding all possible combinations

35+175+210+70+5

= 495ways

3 0
3 years ago
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